Infix expression 计算 without '(' and ')'

#include<iostream>
#include<stack>
#include<string>
using namespace std; char compare(char tp, char op)
{
if (((tp == '+' || tp == '-') && (op == '*' || op == '/')) || (tp == '#'))
return '<';
return '>';
} int compute(int n1, int n2, char op)
{
if (op == '+')
return n1 + n2;
else if (op == '-')
return n1 - n2;
else if (op == '*')
return n1*n2;
else if (op == '/')
return n2 / n1;
} int main()
{
stack<char>num;
stack<char>oper; oper.push('#'); string s;
cin >> s; for (int i = 0; i<s.length(); i++)
{
if (s[i] == '0' || s[i] == '1' || s[i] == '2' || s[i] == '3' || s[i] == '4' || s[i] == '5' || s[i] == '6' || s[i] == '7' || s[i] == '8' || s[i] == '9')
num.push(s[i]);
else
{
char comp = compare(oper.top(), s[i]);
if (comp == '<')
oper.push(s[i]);
else if (comp == '>')
{
int num1 = num.top()-'0';
num.pop();
int num2 = num.top()-'0';
num.pop();
int result = compute(num1, num2, oper.top());
num.push(result+'0');
oper.pop();
oper.push(s[i]);
}
}
} if (num.size() != 1)
{
while (oper.top() != '#')
{
int num1 = num.top()-'0';
num.pop();
int num2 = num.top()-'0';
num.pop();
int result = compute(num1, num2, oper.top());
num.push(result+'0');
oper.pop();
}
} cout << num.top() << endl; return 0;
}

  

上一篇:Visual Studio 2019 正式版 更新内容


下一篇:HDU 3835 R(N)(枚举)