H面试程序(16): 简单选择排序

#include<stdio.h>
#include<assert.h> void display(int * a, int n)
{
assert(a);
for(int i = 0; i < n; i++)
{
printf("%d,",a[i]);
}
printf("\n");
} void swap(int * a, int * b)
{
assert(a);
assert(b);
int temp;
temp = *a;
*a = *b;
*b = temp;
} void select_sort(int * a, int n)
{
assert(a);
int i, j,min;
for( i = 0; i < n-1 ; i++) //i 0 ~ n-2
{
min = a[i]; //每次选择一个作为最小值 for( j = i; j < n; j++) // j i ~ n-1
{
if(a[j] < min)
{
swap(&(a[j]), &(a[i]));
}
}
}
} int main()
{
int a[10] ={2, 1, 3, 4, 5, 7,2,3, 6, 1};
int num = sizeof(a)/sizeof(int);
printf("before_sort:");
display(a, num);
select_sort(a,num);
printf("after_sort:");
display(a, num);
return 0; }
#include <stdio.h>
#include <time.h> //交换两个数据
void swap(int *a, int *b)
{
int temp;
temp = *a;
*a = *b;
*b = temp;
} //显示交换后的数组
void display_array( int a[], int n )
{
int i;
for( i = 0; i < n; i++ )
printf( "%d ", a[i] );
} //选择排序
void select_sort( int a[], int n )
{ int i ,j; for(i = 0; i<n-1 ; i++ )
{
int min = a[i]; //每次都设定最小的数,i 0 ~ 8
for(j =i+1; j <n; j++) // 将a[i]~ a[9]的数于当前最小的数进行比较,如果小于当前最小数就交换
{
if(a[j] < min)
{
swap(&(a[j]), &(a[i]));
}
}
} } int main()
{
clock_t start, finish;
start = clock(); int n = 10;
int a[] = { 2, 1, 3, 4, 5, 7, 6, 8 ,2,4};
printf( "Before sorting: " );
display_array( a, n ); select_sort( a, n );
printf( "After sorting: " );
display_array( a, n );
finish = clock();
printf("\n本次计算一共耗时: %f秒\n\n", (double)(finish-start)/CLOCKS_PER_SEC);
return 0;
}
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