patindex( '%[^-^0-9]% ',col)=0

:表示包含正数或者负数。或者0

即表示，数字的字段！

select * from tb where patindex('%[^0-9]%',col) = 0

select * from 表名 where isnull(字段名,'')<>''

同时排除空值和null的情况

select coopmedcode,patientname,sum(freefee) as total   from

(select coopmedcode,patientname,freefee from dbo.o_CbZyBxDj

union all

select coopmedcode,patientname,freefee from dbo.s_CbZyBxDj ) a  group by coopmedcode,patientname order by total desc

update PAS_D set _enable='Y' where ((fun_id='A1A' and pas_m_id<>'A1') or (fun_id='A1A' and pas_m_id<>'A2'))不等

delete from tb

where 车牌号 in (select  车牌号  from tb  group  by  车牌号  having  count(车牌号) > 1)

 id not  in (select min( id)  from tb  group  by  车牌号  having  count(车牌号) > 1) 

 select * from syscolumns    数据库所有列

 set ANSI_NULLS ON

set QUOTED_IDENTIFIER ON

go

--select dbo.[Get_StrArrayStrOfIndex] ('123,1231,12',',',1)

ALTER function [dbo].[Get_StrArrayStrOfIndex]

(

 @str varchar(1024),  --要分割的字符串

 @split varchar(10),  --分隔符号

 @index int --取第几个元素

)

returns varchar(1024)

as

begin

 declare @location int

 declare @start int

 declare @next int

 declare @seed int

 set @str=ltrim(rtrim(@str))

 set @start=1

 set @next=1

 set @seed=len(@split)

 set @location=charindex(@split,@str)

 while @location<>0 and @index>@next

 begin

   set @start=@location+@seed

   set @location=charindex(@split,@str,@start)

   set @next=@next+1

 end

 if @location =0 select @location =len(@str)+1

--这儿存在两种情况：1、字符串不存在分隔符号 2、字符串中存在分隔符号，跳出while循环后，@location为0，那默认为字符串后边有一个分隔符号。

 return substring(@str,@start,@location-@start)

end