Codeforces Round #277 (Div. 2)D(树形DP计数类)

D. Valid Sets
time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

As you know, an undirected connected graph with n nodes and n - 1 edges
is called a tree. You are given an integer d and a tree consisting of n nodes.
Each node i has a value ai associated
with it.

We call a set S of tree nodes valid if following conditions are satisfied:

  1. S is non-empty.
  2. S is connected. In other words, if nodes u and v are
    in S, then all nodes lying on the simple path between u and v should
    also be presented in S.
  3. Codeforces Round #277 (Div. 2)D(树形DP计数类).

Your task is to count the number of valid sets. Since the result can be very large, you must print its remainder modulo 1000000007(109 + 7).

Input

The first line contains two space-separated integers d (0 ≤ d ≤ 2000)
and n (1 ≤ n ≤ 2000).

The second line contains n space-separated positive integers a1, a2, ..., an(1 ≤ ai ≤ 2000).

Then the next n - 1 line each contain pair of integers u and v (1 ≤ u, v ≤ n)
denoting that there is an edge between u and v.
It is guaranteed that these edges form a tree.

Output

Print the number of valid sets modulo 1000000007.

Sample test(s)
input
1 4
2 1 3 2
1 2
1 3
3 4
output
8
input
0 3
1 2 3
1 2
2 3
output
3
input
4 8
7 8 7 5 4 6 4 10
1 6
1 2
5 8
1 3
3 5
6 7
3 4
output
41
Note

In the first sample, there are exactly 8 valid sets: {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {3, 4} and {1, 3, 4}.
Set {1, 2, 3, 4} is not valid, because the third condition isn't satisfied. Set {1, 4} satisfies
the third condition, but conflicts with the second condition.

题意:RT

思路:树形DP。dp[u]表示以u为根。且它的全部子树的点v的权值都不超过它。且满足 w[u]-w[v]<=d 的方案数

            对于每一个点为根这样算一遍就好了,注意减去算重的情况,即相邻多个点的权值相等,能够用点的代号去重(即规定仅仅能从代号大的往小的DP)

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