题意:一杯水有n的容量,问有多少种方法可以喝完。
析:找规律,找出前几个就发现规律了,就是2的多少次幂。
代码如下:
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cmath>
#include <iostream>
#include <cstring>
#include <set>
#include <queue>
#include <algorithm>
#include <vector>
#include <map>
using namespace std ;
typedef long long LL;
typedef pair<int, int> P;
const int INF = 0x3f3f3f3f;
const double inf = 0x3f3f3f3f3f3f3f;
const double eps = 1e-8;
const int maxn = 1000 + 5;
const int dr[] = {0, 0, -1, 1};
const int dc[] = {-1, 1, 0, 0};
int n, m;
struct node{
string s;
int id;
bool operator < (const node &p) const{
return p.id < id;
}
};
vector<node> v; int main(){
int T; cin >> T;
while(T--){
scanf("%d", &n);
printf("1");
for(int i = 1; i < n; ++i)
printf("0");
printf("\n");
}
return 0;
}