我正在使用RDFLIB在带有ntriples的3个数据集(A,B,C)之间构建图形.

目标：图表包含那些数据集A-> B,B-> C和C-> A之间的链接,我想通过确保从A发出的链接引用回相同的条目来检查这些链接的一致性在一个.

问题：一旦我迭代A-> B中的链接,我想在B-> C中查找相应的条目(可能多于一个),并且对于C-> A,查找相同的条目,是否存在通过了解主题而不迭代所有条目来查找对象的方法？

解决方法:

is there a way to look up objects by knowing the subject without iterating over all entries?

答案是肯定的.您可以使用不同的机制：(a)使用限制进行迭代;或(b)发出SPARQL查询.

(a) constrain the graph and iterate

此解决方案在Graph对象上使用RDFLib三元组函数.见this reference.

#Parse the file
g = rdflib.Graph()
g.parse("yourdata.nquads")
subject = article = rdflib.term.URIRef("http://www.someuri.org/for/your/subject")

# (subject,None,None) represents a constrain to iterate over the graph. By setting
# any of the three elements in the triple you constrain by any combination of subject,
# predicate or object. In this case we only  constrain by subject.
for triple in g.triples((subject,None,None)):
    print triple

(b) issue a SPARQL query

使用SPARQL standard的更标准的解决方案.

rdflib.plugin.register('sparql', rdflib.query.Processor,
                       'rdfextras.sparql.processor', 'Processor')
rdflib.plugin.register('sparql', rdflib.query.Result,
                       'rdfextras.sparql.query', 'SPARQLQueryResult')

 #Parse the file
g = rdflib.Graph()
g.parse("yourdata.nquads")

query = """
    SELECT ?pred ?obj WHERE {
         <http://www.someuri.org/for/your/subject> ?pred ?obj
    }
    """
for row in g.query(query):
    print "Predicate:%s Object:%s"%(row[0],row[1])