Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ times.
n/2 ⌋
You may assume that the array is non-empty and the majority element always exist in the array.
Credits:
Special thanks to @ts for adding this problem and creating all test cases.
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public class Solution {
public int majorityElement(int[] num) {
int last=num[0];
int cnt=1;
for(int i=1;i<num.length;i++){
if(num[i]!=last){
cnt--;
if(cnt==0){
last=num[i];
cnt=1;
}
}else{
cnt++;
}
}
return last;
}
}