BestCoder Round #73 (div.2)

1001 Rikka with Chess

ans = n / 2 + m / 2

1002 Rikka with Graph

题意:n + 1条边,问减去至少一条使剩下的图连通的方案数。

分析:原来暴力选一条或两条就行了,脑子笨了。判连通用BFS或并查集,此题并查集更好

#include <cstdio>
#include <cmath>
#include <cstring>
#include <algorithm>
#include <vector>
#include <map>
#include <string>
#include <set>
using namespace std; typedef long long ll;
const int N = 1e2 + 5;
struct DSU {
int rt[N];
DSU() {
memset (rt, -1, sizeof (rt));
}
int Find(int x) {
return rt[x] == -1 ? x : rt[x] = Find (rt[x]);
}
void Union(int x, int y) {
x = Find (x); y = Find (y);
if (x == y) return ;
rt[x] = y;
}
bool same(int x, int y) {
return Find (x) == Find (y);
}
};
int u[N], v[N]; int main(void) {
int T; scanf ("%d", &T);
while (T--) {
int n; scanf ("%d", &n);
for (int i=0; i<n+1; ++i) {
scanf ("%d%d", u+i, v+i);
}
int ans = 0;
for (int i=0; i<n+1; ++i) {
DSU dsu; int edge = 0;
for (int j=0; j<n+1; ++j) {
if (i == j) continue;
if (!dsu.same (u[j], v[j])) {
dsu.Union (u[j], v[j]);
edge++;
}
if (edge == n - 1) break;
}
if (edge == n - 1) ans++;
}
for (int i=0; i<n+1; ++i) {
for (int j=i+1; j<n+1; ++j) {
DSU dsu; int edge = 0;
for (int k=0; k<n+1; ++k) {
if (k == i || k == j) continue;
if (!dsu.same (u[k], v[k])) {
dsu.Union (u[k], v[k]);
edge++;
}
if (edge == n - 1) break;
}
if (edge == n - 1) ans++;
}
}
printf ("%d\n", ans);
} return 0;
}

1003 Rikka with Array

待补

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