binary and out mode to open a file

When I use binary and out mode to open a exist file, and to modify the 4th and 8th byte data to 0x78, I found that the whole file will be rewrite, like below:

#include <fstream>
#include <iostream>
using namespace std; int main(int argc, char **argv)
{
fstream out;
out.open("./test.txt", ios_base::binary | ios_base::out); uint8_t data = 0x78; out.seekp(4, ios_base::beg);
out.write((char *)&data, 1); out.seekp(8, ios_base::beg);
out.write((char *)&data, 1); out.close();
return 0;
}

  And the file original data is :

FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF

  But the file modified is:

00 00 00 00 78 00 00 00 78

  I have tried ios::app and ios::ate, the ios::app will out put my data at the end of the file and the skeep do not work.

  Finally, I thought out that the file is just a out file, so the api will not see the original data of the file, so I should add the ios::in.

#include <fstream>
#include <iostream>
using namespace std; int main(int argc, char **argv)
{
fstream out;
out.open("./test.txt", ios_base::binary | ios_base::out | ios_base::in); uint8_t data = 0x78; out.seekp(4, ios_base::beg);
out.write((char *)&data, 1); out.seekp(8, ios_base::beg);
out.write((char *)&data, 1); out.close();
return 0;
}

  

  And finally, I got the right data.

FF FF FF FF 78 FF FF FF 78 FF FF FF FF FF FF FF

  

上一篇:opencv处理验证码python代码


下一篇:Maven学习(五)-- 聚合与继承