公式 w = y + y/4 + c/4 - 2*c + 26 * (m+1)/10 + d - 1;

m假设是1 2 月份 y要倒退1年 m += 12

y是年份的后两位 y = year%100

c是世纪 c = year/100

 

#include <cstdio>

#include <cstring>

using namespace std;

char a[7][10] = {"sunday", "monday", "tuesday", "wednesday", "thursday", "friday", "saturday"};

int main()

{

	int y, m, d;

	while(scanf("%d %d %d", &y, &m, &d) != EOF)

	{

		if(m < 3)

		{

			y--;

			m += 12;

		}

		int c = y / 100;

		y = y % 100;

		int w = y + y/4 + c/4 - 2*c + 26 * (m+1)/10 + d - 1;

		printf("%s\n", a[(w%7+7)%7]);

	}

	return 0;

}

 

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