# 列表
# lst = ["光头强", 1, True, {}, (1, ), {123}, ["周杰伦",[], "周杰", "结论"]]
# print(lst)

# 索引和切片
# lst = ["天龙八部", "西游记", "红楼梦", "银平煤", "绿平煤"]
# print(lst[3])
# print(lst[-3])
# print(lst)
# print(lst[1:4]) # 切片，原来是什么类型. 得到的就是什么类型
# print(lst[-1::-2]) # 倒着切

# lst = ["凡人修仙传", "诛仙", "神墓"]
# # 添加 append() 追加. 在后面添加
# lst.append("看见")
# lst.append("追风筝的人")
#
# # 插入 insert(位置, 元素), 效率相对比较低
# lst.insert(1, "琴帝")
#
# # 迭代添加, 把传递进去的参数进行迭代. 把每一项添加到列表的末尾
# lst.extend(["胡辣汤","猪蹄子", "猪头肉", "五花肉"])
#
# print(lst)

# # 删除
# lst = ["斗破苍求", "手机", "爵迹", "满城尽带黄金甲", "三生三世十里桃花"]
#
# # # pop() 默认从后往前删
# # lst.pop()
# # # pop(索引) 按照索引位置删除
# # lst.pop(1)
#
# # remove(元素) 移除
# # lst.remove("满城尽带黄金甲") # 当元素不存在的时候会报错
#
# # del lst[::2] # 用切片或者索引删除 不常用
# lst.clear() # 清空.
#
# print(lst)

# 修改
# lst = ["苏秦", "武大", "武二", "宝元", "李诞", "池子", "王建国"]
# # lst[3] = "松江" # 通过索引修改 index out of range 索引下标越界
# # print(lst)
# # lst[1:3] = ["麻花藤"] # 迭代更新(不常用)
# # print(lst)
# lst[1:5:2] = ["麻花藤", "码云"] # 坑: 如果步长不是1. 元素的个数必须要和切片的个数一致
# print(lst)

# lst = ["alex", "wusir", "胡辣汤"]
# # 把列表中的wusir替换成大写 WUSIR
# # 首先你要获取到2元素
# # 变成大写
# # 塞回去(必须要放回去)
# lst[1] = lst[1].replace("wusir", "WUSIR")
# print(lst)

# 查询, 列表是一个可迭代对象
# lst = ["jay", "wlh", "lzw", "wf"]
# for item in lst: # item是lst中的每一项
# print(item)

# for i in 123: # 'int' object is not iterable
# print(i)

lst = [["张艺谋", "冯小刚", "陈凯歌"], ["李安", "王家卫", "王晶"], ["周杰伦",["abc", "alex_wusir", ["胡辣汤", "c"]], "风扇哥"]]
# print(lst[1][1][2])

# 把王晶换成"贾樟柯"

# lst[1][2] = "贾樟柯"
# print(lst)
# $$$$$$$
# 降维操作 ["哈哈", "hehe", "houhou"] 一维 [[1,2,3], [12,4,5], [6,7,8]] 二维
# 数数
lst[2][1][1] = lst[2][1][1].replace("_", "$")
print(lst)

# lst = ["太白", "太白", "太黑", "日天", "女神", "alex", "太白"]
#
# print(lst.count("太白")) # 查看xxx元素出现的次数

# lst = [1, 8,12,22,1,1,2,33,4,5]
# # lst.sort() # 排序. 默认升序
# lst.sort(reverse=True) # reverse 反向, 降序
# print(lst)

# lst = ["赤木", "樱木花道", "流川枫", "三井"]
# lst.reverse() # 把列表翻转
# print(lst)

# lst= [1,2,3,4,5,"胡辣汤"]
# print(len(lst)) # 查看列表中元素的个数

# list # 按住ctrl +鼠标左键

# 元组用()表示, 只读列表. 冯提莫
# tu = ("DNF", "LOL", "王者荣耀", "QQ飞车", "炫舞", {}, tuple(), [])
# print(tu)
# # tu[1] = "呵呵" # 'tuple' object does not support item assignment
# print(tu)

# 元组也有索引和切片
# print(tu[3:5])
# print(tu[3:7:2])

# 元组有坑
# 空元祖
# tu = tuple() # 固定写法
# 元组中如果只有一个元素
# tu = (1) # 不是元组 <class 'int'>
# tu = (1, ) # 这个是元组 <class 'tuple'>
# print(type(tu))

# 好习惯: 写元组的时候末尾加个逗号

# tu = ("锅包肉", "酸菜炖粉条+五花肉", "红烧鲤鱼", "红烧肉")
# # 元组也是可迭代的
# for item in tu: # 可以使用for循环
# print(item)

tu = (1, "哈哈", "胡辣汤", ["忍者", "神龟"])
# tu[1] = "呵呵" # 元组不可变
tu[3] = ["我是新列表"] # 改变了指向. 报错
tu[3].append("孙悟空") # 元组没改. 该的是元素内部 没有改变元组的指向. 不报错
print(tu)

# i = 1
# while i <=100:
# print(i)
# i += 1

# range(参数) [0,参数)
# for i in range(20): # range()可以被迭代 0-9
# print(i)

# range(参数1, 参数2) [参数1, 参数2) 切片
# for i in range(10, 20):
# print(i)

# range(参数1, 参数2, 参数3) [参数1, 参数2) 每隔参数3个位置取一个
# for i in range(10, 20, 3):
# print(i)

# lst = ["周杰伦", "动画城", "大风车", "随便加", "宝宝", "孟孟", "萌萌", "孟萌"]

# for item in lst: # 只能拿到元素. 获取不到索引
# print(item)

# for i in range(len(lst)): # i就是索引 lst[i]元素
# print(i, lst[i])