<servlet>
<servlet-name>login</servlet-name>
<servlet-class>com.jd.login.UI.LoginUIServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>login</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
若将servlet的url-pattern配置为“/*”时会拦截内部所有请求，使所有请求都由com.jd.login.UI.LoginUIServlet来处理，所以当项目跑起来后会出现栈溢出错误：java.lang.*Error
@WebServlet(name = "LoginUIServlet",value="/servlet/LoginUIServlet")
public class LoginUIServlet extends HttpServlet {
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
//出现死循环，因为所有请求都被拦截
request.getRequestDispatcher("/WEB-INF/pages/login.jsp").forward(request,response);
} protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
this.doPost(request,response);
}
}
栈溢出异常如下：
解决：
将web.xml中的servlet的url-pattern配置为具体的路径
<servlet>
<servlet-name>login</servlet-name>
<servlet-class>com.jd.login.UI.LoginUIServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>login</servlet-name>
<url-pattern>/servlet/LoginUIServlet</url-pattern>
</servlet-mapping>
检验：
在浏览器中输入localhost/servlet/LoginUIServlet，结果如下
备注：在IDEA中跑起来的web项目，在浏览器中访问不要添加应用名称。