11-高级子查询

  1 --子查询
  2 --子查询 (内查询) 在主查询执行之前执行
  3 --主查询(外查询)使用子查询的结果
  4 --问题:查询工资大于149号员工工资的员工的信息
  5 SELECT last_name
  6 FROM   employees
  7 WHERE  salary > 
  8                 (SELECT salary
  9                  FROM   employees
 10                  WHERE  employee_id = 149) ;
 11  
 12 --多利子查询                
 13 --主查询与子查询返回的多个列进行比较
 14 --主查询与子查询返回的多个列进行比较
 15 --多列子查询中的比较分为两种:
 16 --成对比较
 17 --不成对比较
 18 
 19 --成对比较举例
 20 --问题:查询与141号或174号员工的manager_id和department_id相同的其他员工的employee_id, manager_id, department_id  
 21 SELECT    employee_id, manager_id, department_id
 22 FROM    employees
 23 WHERE  (manager_id, department_id) IN
 24                       (SELECT manager_id, department_id
 25                        FROM   employees
 26                        WHERE  employee_id IN (141,174))
 27 AND    employee_id NOT IN (141,174);
 28 
 29 --不成对比较举例
 30 SELECT  employee_id, manager_id, department_id
 31 FROM    employees
 32 WHERE   manager_id IN                   (SELECT  manager_id
 33                    FROM    employees
 34                    WHERE   employee_id IN (174,141))
 35 AND     department_id IN                   (SELECT  department_id
 36                    FROM    employees
 37                    WHERE   employee_id IN (174,141))
 38 AND    employee_id NOT IN(174,141);
 39 
 40 --在 FROM 子句中使用子查询
 41 --问题:返回比本部门平均工资高的员工的last_name, department_id, salary及平均工资
 42 --方法一
 43 select last_name,department_id,salary,
 44       (select avg(salary)from employees e3 
 45        where e1.department_id = e3.department_id 
 46        group by department_id) avg_salary
 47 from employees e1
 48 where salary > 
 49          (select avg(salary)
 50           from employees e2  
 51           where e1.department_id = e2.department_id
 52           group by department_id
 53           )
 54 
 55 --方法二
 56 SELECT  a.last_name, a.salary, 
 57         a.department_id, b.salavg
 58 FROM    employees a, (SELECT   department_id, 
 59                       AVG(salary) salavg
 60                       FROM     employees
 61                       GROUP BY department_id) b
 62 WHERE   a.department_id = b.department_id
 63 AND     a.salary > b.salavg;
 64 
 65 --单列子查询表达式
 66 --单列子查询表达式是在一行中只返回一列的子查询
 67 --Oracle8i 只在下列情况下可以使用, 例如:
 68 --  SELECT 语句 (FROM 和 WHERE 子句)
 69 --  INSERT 语句中的VALUES列表中
 70 --Oracle9i中单列子查询表达式可在下列情况下使用:
 71 --  DECODE  和 CASE
 72 --  SELECT 中除 GROUP BY 子句以外的所有子句中
 73 
 74 --在 CASE 表达式中使用单列子查询
 75 --问题:显式员工的employee_id,last_name和location。其中,若员工department_id与location_id为1800的department_id相同,则location为’Canada’,其余则为’USA’。
 76 SELECT employee_id, last_name,
 77        (CASE
 78         WHEN department_id =(SELECT department_id FROM departments WHERE location_id = 1800)              
 79         THEN 'Canada' ELSE 'USA' END) location
 80 FROM   employees;
 81 
 82 --在 ORDER BY 子句中使用单列子查询
 83 --问题:查询员工的employee_id,last_name,要求按照员工的department_name排序
 84 SELECT   employee_id, last_name
 85 FROM     employees e
 86 ORDER BY (SELECT department_name
 87           FROM departments d
 88           WHERE e.department_id = d.department_id);
 89 
 90 --相关子查询
 91 --相关子查询按照一行接一行的顺序执行,主查询的每一行都执行一次子查询
 92 --问题:查询员工中工资大于本部门平均工资的员工的last_name,salary和其department_id
 93 SELECT last_name, salary, department_id
 94 FROM   employees outer
 95 WHERE  salary >(SELECT AVG(salary)
 96                 FROM   employees
 97                 WHERE  department_id =  outer.department_id) ;
 98 
 99 --问题:若employees表中employee_id与job_history表中employee_id相同的数目不小于2,输出这些相同id的员工的employee_id,last_name和其job_id
100 SELECT e.employee_id, last_name,e.job_id
101 FROM   employees e 
102 WHERE  2 <= (SELECT COUNT(*)
103              FROM   job_history 
104              WHERE  employee_id = e.employee_id);
105 
106 --EXISTS 操作符
107 --EXISTS 操作符检查在子查询中是否存在满足条件的行
108 --如果在子查询中存在满足条件的行:
109 --    不在子查询中继续查找
110 --    条件返回 TRUE
111 --如果在子查询中不存在满足条件的行:
112 --    条件返回 FALSE
113 --    继续在子查询中查找
114 --问题:查询公司管理者的employee_id,last_name,job_id,department_id信息
115 SELECT employee_id, last_name, job_id, department_id
116 FROM   employees outer
117 WHERE  EXISTS ( SELECT 'X'
118                  FROM   employees
119                  WHERE  manager_id = 
120                         outer.employee_id);
121                         
122 --NOT EXISTS 操作符应用举例
123 --问题:查询departments表中,不存在于employees表中的部门的department_id和department_name
124 SELECT department_id, department_name
125 FROM departments d
126 WHERE NOT EXISTS (SELECT 'X'
127                   FROM   employees
128                   WHERE  department_id 
129                          = d.department_id);
130 
131 --相关更新
132 --使用相关子查询依据一个表中的数据更新另一个表的数据
133 --eg:1
134 ALTER TABLE employees
135 ADD(department_name VARCHAR2(14));
136 --eg:2
137 UPDATE employees e
138 SET    department_name = 
139               (SELECT department_name 
140                FROM   departments d
141                WHERE  e.department_id = d.department_id);
142 
143 --相关删除
144 --问题:删除表employees中,其与emp_history表皆有的数据
145 DELETE FROM employees E
146 WHERE employee_id =  
147            (SELECT employee_id
148             FROM   emp_history 
149             WHERE  employee_id = E.employee_id);
150 
151 --WITH 子句
152 --使用 WITH 子句, 可以避免在 SELECT 语句中重复书写相同的语句块
153 --WITH 子句将该子句中的语句块执行一次并存储到用户的临时表空间中
154 --使用 WITH 子句可以提高查询效率
155 --问题:查询公司中各部门的总工资大于公司中各部门的平均总工资的部门信息
156 WITH 
157 dept_costs  AS (
158                 SELECT  d.department_name, SUM(e.salary) AS dept_total
159                 FROM    employees e, departments d
160                 WHERE   e.department_id = d.department_id
161                 GROUP BY d.department_name),
162 avg_cost    AS (
163                  SELECT SUM(dept_total)/COUNT(*) AS dept_avg
164                  FROM   dept_costs)
165 SELECT * 
166 FROM   dept_costs 
167 WHERE  dept_total >
168         (SELECT dept_avg 
169          FROM avg_cost)
170 ORDER BY department_name;

 

eg:

 1 --查询员工的last_name, department_id, salary.其中员工的salary,department_id与有奖金的任何一个员工的salary,department_id相同即可
 2 select last_name, department_id, salary
 3 from employees 
 4 where (salary,department_id) in (
 5                                  select salary,department_id
 6                                  from employees
 7                                  where commission_pct is not null
 8                                     );
 9 
10 --选择工资大于所有JOB_ID = 'SA_MAN'的员工的工资的员工的last_name, job_id, salary
11 select last_name, job_id, salary
12 from employees
13 where salary > all(
14                   select salary
15                   from employees
16                   where job_id = 'SA_MAN'
17                   );
18                   
19 --选择所有没有管理者的员工的last_name
20 select last_name
21 from employees e1
22 where not exists (
23               select 'A'
24               from employees e2
25               where e1.manager_id = e2.employee_id
26               );

 

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