// 圆内，求离圆心最远的整数点 hiho一下第111周 Farthest Point

 // 思路：直接暴力绝对T

 // 先确定x范围，每个x范围内，离圆心最远的点一定是y轴两端的点。枚举x的范围，再比较y

 // O(n)

 #include <bits/stdc++.h>

 using namespace std;

 #define LL long long

 const double inf = 123456789012345.0;

 const LL MOD =100000000LL;

 const int N =1e7+;

 #define clc(a,b) memset(a,b,sizeof(a))

 const double eps = 1e-;

 void fre() {freopen("in.txt","r",stdin);}

 void freout() {freopen("out.txt","w",stdout);}

 inline int read() {int x=,f=;char ch=getchar();while(ch>''||ch<'') {if(ch=='-') f=-; ch=getchar();}while(ch>=''&&ch<='') {x=x*+ch-'';ch=getchar();}return x*f;}

 double dis(double a,double b,double c,double d){

     return (a-c)*(a-c)+(b-d)*(b-d);

 }

 int main(){

     double x,y,r;

     double len=-;

     int ans_y,ans_x;

     scanf("%lf%lf%lf",&x,&y,&r);

     for(double i=floor(x+r);i>=ceil(x-r);i--){

         double d=(double)sqrt(r*r-(i-x)*(i-x));

         double y1=floor(d+y),y2=ceil(y-d);

         if(dis(x,y,i,y1)>len){

             len=dis(x,y,i,y1);

             ans_x=i,ans_y=y1;

         }

         if(dis(x,y,i,y2)>len){

             len=dis(x,y,i,y2);

             ans_x=i,ans_y=y2;

         }

     }

     printf("%d %d\n",ans_x,ans_y);

     return ;

 }