MS SQL Server没有split()函数，但是我们可以写一个Table-valued Functions定义函数[dbo].[udf_SplitStringToTable] ：
CREATE FUNCTION [dbo].[udf_SplitStringToTable]
(
@string NVARCHAR(MAX),
@delimiter CHAR(1)
)
RETURNS @result TABLE([ID] INT IDENTITY(1,1),value NVARCHAR(MAX)
)
BEGIN
DECLARE @start INT, @end INT
SELECT @start = 1, @end = CHARINDEX(@delimiter, @string)
WHILE @start < LEN(@string) + 1
BEGIN
IF @end = 0
SET @end = LEN(@string) + 1 INSERT INTO @result (value) VALUES (SUBSTRING(@string, @start, @end - @start))
SET @start = @end + 1
SET @end = CHARINDEX(@delimiter, @string, @start)
END
RETURN
END
Source Code
再写另外一个Scalar-valued Function自定义函数[dbo].[udf_SplitString]:
CREATE FUNCTION [dbo].[udf_SplitString]
(
@string NVARCHAR(MAX),
@delimiter CHAR(1),
@index INT
)
RETURNS NVARCHAR(MAX)
AS
BEGIN
DECLARE @rtn NVARCHAR(MAX)
SELECT @rtn = [value] FROM [dbo].[udf_SplitStringToTable] (@string,@delimiter) WHERE [ID] = @index
RETURN @rtn
END
GO
Source Code
上面代码示例中@index参数即是你想获取第几个字符串，举个例子吧：