评分卡
- 建立逻辑回归模型
- 对模型进行评分映射
逻辑回归表达式
\[ y = \frac{1}{1 + e^{-\theta}} \]
\[ \theta = WX + B \]
sigmoid函数
\[ sigmoid(x) = \frac{1}{1 + e^{-x}} \]
sigmoid函数的导数
\[ \delta sigmoid(x) = \delta{\frac{1}{1 + e^{-x}}} = \delta{\frac{e^{-x}}{(1 + e^{-x})^2}} = \delta{\frac{1}{1 + e^{-x}} * \frac{e^{-x}}{1 + e^{-x}}} = sigmoid(x) * \frac{1 + e^{-x} - 1}{1 + e^{-x}} = sigmoid(x) * (1 - sigmoid(x)) \]
损失函数(Cross-entropy, 交叉熵损失函数)
信息熵: \(-PlogP\)(P是概率, 小于1, 取反之后就是正数了), 这个值代表的是信息量, 如果值越大代表对当前情况越不确定, 信息不足.
\[ loss = -\sum{{y_t}log{y_p} + (1 - y_t)log{(1 - y_p)}} \]
\(y_t\): 真实的Y值, 需要进行独热编码
\(y_p\): 预测的Y值
交叉熵求导
\[ \frac{\delta loss}{\delta Y_p} = -\frac{\delta Y_tlogY_p}{\delta Y_p} = \sum_n^N{-\frac{Y_i}{P_i} + \frac{1 - Y_i}{1 - P_i}} \]
准确率计算
混淆矩阵
| T\Pre | Positive | Negative |
|---|---|---|
| Positive | TP | FN |
| Negative | FP | TN |
评估指标
召回率计算
\[ recall = \frac{TP}{TP + FP} \]
精准率计算
\[ precision = \frac{TP}{TP + FN} \]
import pandas as pd
from sklearn.metrics import roc_auc_score,roc_curve,auc
from sklearn.model_selection import train_test_split
from sklearn import metrics
from sklearn.linear_model import LogisticRegression
import numpy as np
import random
import mathdata = pd.read_csv('Acard.txt')
data.head()| obs_mth | bad_ind | uid | td_score | jxl_score | mj_score | rh_score | zzc_score | zcx_score | person_info | finance_info | credit_info | act_info | |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 0 | 2018-10-31 | 0.0 | A10000005 | 0.675349 | 0.144072 | 0.186899 | 0.483640 | 0.928328 | 0.369644 | -0.322581 | 0.023810 | 0.00 | 0.217949 |
| 1 | 2018-07-31 | 0.0 | A1000002 | 0.825269 | 0.398688 | 0.139396 | 0.843725 | 0.605194 | 0.406122 | -0.128677 | 0.023810 | 0.00 | 0.423077 |
| 2 | 2018-09-30 | 0.0 | A1000011 | 0.315406 | 0.629745 | 0.535854 | 0.197392 | 0.614416 | 0.320731 | 0.062660 | 0.023810 | 0.10 | 0.448718 |
| 3 | 2018-07-31 | 0.0 | A10000481 | 0.002386 | 0.609360 | 0.366081 | 0.342243 | 0.870006 | 0.288692 | 0.078853 | 0.071429 | 0.05 | 0.179487 |
| 4 | 2018-07-31 | 0.0 | A1000069 | 0.406310 | 0.405352 | 0.783015 | 0.563953 | 0.715454 | 0.512554 | -0.261014 | 0.023810 | 0.00 | 0.423077 |
# 看一下月份分布，用最后一个月做为跨时间验证集合
data.obs_mth.unique()array(['2018-10-31', '2018-07-31', '2018-09-30', '2018-06-30',
'2018-11-30'], dtype=object)# 划分训练集和验证集
train = data[data.obs_mth != '2018-11-30'].reset_index().copy()
val = data[data.obs_mth == '2018-11-30'].reset_index().copy()# 这是我们全部的变量，info结尾的是自己做的无监督系统输出的个人表现，score结尾的是收费的外部征信数据
feature_lst = ['person_info','finance_info','credit_info','act_info','td_score','jxl_score','mj_score','rh_score']x = train[feature_lst]
y = train['bad_ind']
val_x = val[feature_lst]
val_y = val['bad_ind']
lr_model = LogisticRegression(C=0.1)
lr_model.fit(x,y)E:\Anaconda3\envs\sklearn\lib\site-packages\sklearn\linear_model\logistic.py:432: FutureWarning: Default solver will be changed to 'lbfgs' in 0.22. Specify a solver to silence this warning.
FutureWarning)
LogisticRegression(C=0.1, class_weight=None, dual=False, fit_intercept=True,
intercept_scaling=1, max_iter=100, multi_class='warn',
n_jobs=None, penalty='l2', random_state=None, solver='warn',
tol=0.0001, verbose=0, warm_start=False)模型评价
- KS值
- ROC曲线
ROC
描绘的是不同的截断点时，并以FPR和TPR为横纵坐标轴，描述随着截断点的变小，TPR随着FPR的变化。
纵轴：TPR=正例分对的概率 = TP/(TP+FN)，其实就是查全率
横轴：FPR=负例分错的概率 = FP/(FP+TN)
作图步骤：
根据学习器的预测结果（注意，是正例的概率值，非0/1变量）对样本进行排序（从大到小）-----这就是截断点依次选取的顺序
按顺序选取截断点，并计算TPR和FPR---也可以只选取n个截断点，分别在1/n，2/n，3/n等位置
连接所有的点（TPR，FPR）即为ROC图
KS值
作图步骤：
根据学习器的预测结果（注意，是正例的概率值，非0/1变量）对样本进行排序（从大到小）-----这就是截断点依次选取的顺序
按顺序选取截断点，并计算TPR和FPR ---也可以只选取n个截断点，分别在1/n，2/n，3/n等位置
横轴为样本的占比百分比（最大100%），纵轴分别为TPR和FPR，可以得到KS曲线
TPR和FPR曲线分隔最开的位置就是最好的”截断点“，最大间隔距离就是KS值，通常>0.2即可认为模型有比较好偶的预测准确性
# 训练集KS
y_pred = lr_model.predict_proba(x)[:,1]
fpr_lr_train,tpr_lr_train,_ = roc_curve(y,y_pred)
train_ks = abs(fpr_lr_train - tpr_lr_train).max()
print('train_ks : ',train_ks)
# 验证集KS
y_pred = lr_model.predict_proba(val_x)[:,1]
fpr_lr,tpr_lr,_ = roc_curve(val_y,y_pred)
val_ks = abs(fpr_lr - tpr_lr).max()
print('val_ks : ',val_ks)
# 训练集AUC
train_auc = auc(fpr_lr_train, tpr_lr_train)
print('train_auc:', train_auc)
# 验证集AUC
val_auc = auc(fpr_lr, tpr_lr)
print('val_auc:', val_auc)
# ROC曲线
from matplotlib import pyplot as plt
plt.plot(fpr_lr_train,tpr_lr_train,label = 'train LR')
plt.plot(fpr_lr,tpr_lr,label = 'evl LR')
plt.plot([0,1],[0,1],'k--') # 虚线
plt.xlabel('False positive rate')
plt.ylabel('True positive rate')
plt.title('ROC Curve')
plt.legend(loc = 'best')
plt.show()train_ks : 0.4144413866157737
val_ks : 0.3709405449809594
train_auc: 0.777913749438214
val_auc: 0.749188849417094# 使用方差膨胀系数做特征筛选
from statsmodels.stats.outliers_influence import variance_inflation_factor
X = np.array(x)
for i in range(X.shape[1]):
print(variance_inflation_factor(X,i))1.3021397545577766
1.9579535743187253
1.289944208916368
2.9681708673324034
3.2871099722760153
3.286493284008913
3.3175087980337827
3.2910065791107597方差膨胀系数VIF越大，说明自变量之间存在共线性的可能性越大。一般来讲，如果方差膨胀因子超过10，则回归模型存在严重的多重共线性。又根据Hair(1995)的共线性诊断标准，当自变量的容忍度大于0.1，方差膨胀系数小于10的范围是可以接受的，表明白变量之间没有共线性问题存在。
import lightgbm as lgb
from sklearn.model_selection import train_test_split
train_x,test_x,train_y,test_y = train_test_split(x,y,random_state=0,test_size=0.2)
def lgb_test(train_x,train_y,test_x,test_y):
clf =lgb.LGBMClassifier(boosting_type = 'gbdt',
objective = 'binary',
metric = 'auc',
learning_rate = 0.1,
n_estimators = 24,
max_depth = 5,
num_leaves = 20,
max_bin = 45,
min_data_in_leaf = 6,
bagging_fraction = 0.6,
bagging_freq = 0,
feature_fraction = 0.8,
)
clf.fit(train_x,train_y,eval_set = [(train_x,train_y),(test_x,test_y)],eval_metric = 'auc')
return clf,clf.best_score_['valid_1']['auc'],
lgb_model , lgb_auc = lgb_test(train_x,train_y,test_x,test_y)
feature_importance = pd.DataFrame({'name':lgb_model.booster_.feature_name(),
'importance':lgb_model.feature_importances_}).sort_values(by=['importance'],ascending=False)
feature_importance[1] training's auc: 0.759467 valid_1's auc: 0.753322
[2] training's auc: 0.809023 valid_1's auc: 0.805658
[3] training's auc: 0.809328 valid_1's auc: 0.803858
[4] training's auc: 0.810298 valid_1's auc: 0.801355
[5] training's auc: 0.814873 valid_1's auc: 0.807356
[6] training's auc: 0.816492 valid_1's auc: 0.809279
[7] training's auc: 0.820213 valid_1's auc: 0.809208
[8] training's auc: 0.823931 valid_1's auc: 0.812081
[9] training's auc: 0.82696 valid_1's auc: 0.81453
[10] training's auc: 0.827882 valid_1's auc: 0.813428
[11] training's auc: 0.828881 valid_1's auc: 0.814226
[12] training's auc: 0.829577 valid_1's auc: 0.813749
[13] training's auc: 0.830406 valid_1's auc: 0.813156
[14] training's auc: 0.830843 valid_1's auc: 0.812973
[15] training's auc: 0.831587 valid_1's auc: 0.813501
[16] training's auc: 0.831898 valid_1's auc: 0.813611
[17] training's auc: 0.833751 valid_1's auc: 0.81393
[18] training's auc: 0.834139 valid_1's auc: 0.814532
[19] training's auc: 0.835177 valid_1's auc: 0.815209
[20] training's auc: 0.837368 valid_1's auc: 0.815205
[21] training's auc: 0.837946 valid_1's auc: 0.815099
[22] training's auc: 0.839585 valid_1's auc: 0.815602
[23] training's auc: 0.840781 valid_1's auc: 0.816105
[24] training's auc: 0.841174 valid_1's auc: 0.816869| name | importance | |
|---|---|---|
| 2 | credit_info | 98 |
| 3 | act_info | 62 |
| 4 | td_score | 54 |
| 5 | jxl_score | 50 |
| 7 | rh_score | 50 |
| 0 | person_info | 49 |
| 1 | finance_info | 47 |
| 6 | mj_score | 46 |
feature_lst = ['person_info','finance_info','credit_info','act_info']
# 训练集
x = train[feature_lst]
y = train['bad_ind']
# 验证集
val_x = val[feature_lst]
val_y = val['bad_ind']
lr_model = LogisticRegression(C=0.1, class_weight='balanced')
lr_model.fit(x,y)
y_pred = lr_model.predict_proba(x)[:,1]
fpr_lr_train,tpr_lr_train,_ = roc_curve(y,y_pred)
train_ks = abs(fpr_lr_train - tpr_lr_train).max()
print('train_ks : ',train_ks)
y_pred = lr_model.predict_proba(val_x)[:,1]
fpr_lr,tpr_lr,_ = roc_curve(val_y,y_pred)
val_ks = abs(fpr_lr - tpr_lr).max()
print('val_ks : ',val_ks)
from matplotlib import pyplot as plt
plt.plot(fpr_lr_train,tpr_lr_train,label = 'train LR')
plt.plot(fpr_lr,tpr_lr,label = 'evl LR')
plt.plot([0,1],[0,1],'k--')
plt.xlabel('False positive rate')
plt.ylabel('True positive rate')
plt.title('ROC Curve')
plt.legend(loc = 'best')
plt.show()E:\Anaconda3\envs\sklearn\lib\site-packages\sklearn\linear_model\logistic.py:432: FutureWarning: Default solver will be changed to 'lbfgs' in 0.22. Specify a solver to silence this warning.
FutureWarning)
train_ks : 0.4482453222991063
val_ks : 0.4198642457760936# 系数
print('变量名单：',feature_lst)
print('系数：',lr_model.coef_)
print('截距：',lr_model.intercept_)变量名单： ['person_info', 'finance_info', 'credit_info', 'act_info', 'td_score', 'jxl_score', 'mj_score', 'rh_score']
系数： [[ 2.49234624 4.35064917 1.83110927 -1.63300006 -0.18766591 -0.11007296
-0.20273074 -0.08850626]]
截距： [-3.53854743]# 生成报告
# 模型
model = lr_model
row_num, col_num = 0, 0
# 分箱的数量
bins = 20
# 预测的概率
Y_predict = [s[1] for s in model.predict_proba(val_x)]
# 标签
Y = val_y
# 样本个数
nrows = Y.shape[0]
# 列表
lis = [(Y_predict[i], Y[i]) for i in range(nrows)]
# 按概率大小排序
ks_lis = sorted(lis, key=lambda x: x[0], reverse=True)
# 每一箱中的样本数量
bin_num = int(nrows/bins+1)
# 负样本数量
bad = sum([1 for (p, y) in ks_lis if y > 0.5])
# 正样本数量
good = sum([1 for (p, y) in ks_lis if y <= 0.5])
bad_cnt, good_cnt = 0, 0
KS = []
BAD = []
GOOD = []
BAD_CNT = []
GOOD_CNT = []
BAD_PCTG = []
BADRATE = []
dct_report = {}
for j in range(bins):
# 每一箱中的list
ds = ks_lis[j*bin_num: min((j+1)*bin_num, nrows)]
# 每一箱中的负样本数量
bad1 = sum([1 for (p, y) in ds if y > 0.5])
# 每一箱中的正样本数量
good1 = sum([1 for (p, y) in ds if y <= 0.5])
bad_cnt += bad1
good_cnt += good1
# 负样本率
bad_pctg = round(bad_cnt/sum(val_y),3)
# bad_rate
badrate = round(bad1/(bad1+good1),3)
ks = round(math.fabs((bad_cnt / bad) - (good_cnt / good)),3)
KS.append(ks)
BAD.append(bad1)
GOOD.append(good1)
BAD_CNT.append(bad_cnt)
GOOD_CNT.append(good_cnt)
BAD_PCTG.append(bad_pctg)
BADRATE.append(badrate)
dct_report['KS'] = KS
dct_report['BAD'] = BAD
dct_report['GOOD'] = GOOD
dct_report['BAD_CNT'] = BAD_CNT
dct_report['GOOD_CNT'] = GOOD_CNT
dct_report['BAD_PCTG'] = BAD_PCTG
dct_report['BADRATE'] = BADRATE
val_repot = pd.DataFrame(dct_report)
val_repot| KS | BAD | GOOD | BAD_CNT | GOOD_CNT | BAD_PCTG | BADRATE | |
|---|---|---|---|---|---|---|---|
| 0 | 0.164 | 69 | 730 | 69 | 730 | 0.210 | 0.086 |
| 1 | 0.271 | 51 | 748 | 120 | 1478 | 0.366 | 0.064 |
| 2 | 0.292 | 23 | 776 | 143 | 2254 | 0.436 | 0.029 |
| 3 | 0.356 | 37 | 762 | 180 | 3016 | 0.549 | 0.046 |
| 4 | 0.364 | 19 | 780 | 199 | 3796 | 0.607 | 0.024 |
| 5 | 0.363 | 16 | 783 | 215 | 4579 | 0.655 | 0.020 |
| 6 | 0.355 | 14 | 785 | 229 | 5364 | 0.698 | 0.018 |
| 7 | 0.363 | 19 | 780 | 248 | 6144 | 0.756 | 0.024 |
| 8 | 0.353 | 13 | 786 | 261 | 6930 | 0.796 | 0.016 |
| 9 | 0.336 | 11 | 788 | 272 | 7718 | 0.829 | 0.014 |
| 10 | 0.313 | 9 | 790 | 281 | 8508 | 0.857 | 0.011 |
| 11 | 0.277 | 5 | 794 | 286 | 9302 | 0.872 | 0.006 |
| 12 | 0.251 | 8 | 791 | 294 | 10093 | 0.896 | 0.010 |
| 13 | 0.234 | 11 | 788 | 305 | 10881 | 0.930 | 0.014 |
| 14 | 0.202 | 6 | 793 | 311 | 11674 | 0.948 | 0.008 |
| 15 | 0.173 | 7 | 792 | 318 | 12466 | 0.970 | 0.009 |
| 16 | 0.134 | 4 | 795 | 322 | 13261 | 0.982 | 0.005 |
| 17 | 0.092 | 3 | 796 | 325 | 14057 | 0.991 | 0.004 |
| 18 | 0.045 | 1 | 798 | 326 | 14855 | 0.994 | 0.001 |
| 19 | 0.000 | 2 | 792 | 328 | 15647 | 1.000 | 0.003 |
from pyecharts.charts import *
from pyecharts import options as opts
from pylab import *
mpl.rcParams['font.sans-serif'] = ['SimHei']
np.set_printoptions(suppress=True)
pd.set_option('display.unicode.ambiguous_as_wide', True)
pd.set_option('display.unicode.east_asian_width', True)
line = (
Line()
.add_xaxis(list(val_repot.index))
.add_yaxis(
"分组坏人占比",
list(val_repot.BADRATE),
yaxis_index=0,
color="red",
)
.set_global_opts(
title_opts=opts.TitleOpts(title="行为评分卡模型表现"),
)
.extend_axis(
yaxis=opts.AxisOpts(
name="累计坏人占比",
type_="value",
min_=0,
max_=0.5,
position="right",
axisline_opts=opts.AxisLineOpts(
linestyle_opts=opts.LineStyleOpts(color="red")
),
axislabel_opts=opts.LabelOpts(formatter="{value}"),
)
)
.add_xaxis(list(val_repot.index))
.add_yaxis(
"KS",
list(val_repot['KS']),
yaxis_index=1,
color="blue",
label_opts=opts.LabelOpts(is_show=False),
)
)
line.render_notebook()# ['person_info','finance_info','credit_info','act_info']
# 算分数onekey
def score(person_info, finance_info, credit_info, act_info):
xbeta = person_info * ( 3.49460978) + finance_info * ( 11.40051582 ) + credit_info * (2.45541981) + act_info * ( -1.68676079) --0.34484897
score = 650-34* (xbeta)/math.log(2)
return score
val['score'] = val.apply(lambda x : score(x.person_info,x.finance_info,x.credit_info,x.act_info) ,axis=1)
fpr_lr,tpr_lr,_ = roc_curve(val_y,val['score'])
val_ks = abs(fpr_lr - tpr_lr).max()
print('val_ks : ',val_ks)
print(val['score'].head())
# 对应评级区间
def level(score):
level = 0
if score <= 600:
level = "D"
elif score <= 640 and score > 600 :
level = "C"
elif score <= 680 and score > 640:
level = "B"
elif score > 680 :
level = "A"
return level
val['level'] = val.score.map(lambda x : level(x) )
val.level.groupby(val.level).count()/len(val)val_ks : 0.4198642457760936
0 514.314551
1 636.487029
2 643.092121
3 668.413494
4 636.487029
Name: score, dtype: float64
level
A 0.144351
B 0.240188
C 0.391299
D 0.224163
Name: level, dtype: float64import seaborn as sns
sns.distplot(val.score,kde=True)
val = val.sort_values('score',ascending=True).reset_index(drop=True)
df2=val.bad_ind.groupby(val['level']).sum()
df3=val.bad_ind.groupby(val['level']).count()
print(df2/df3) E:\Anaconda3\envs\sklearn\lib\site-packages\scipy\stats\stats.py:1713: FutureWarning: Using a non-tuple sequence for multidimensional indexing is deprecated; use `arr[tuple(seq)]` instead of `arr[seq]`. In the future this will be interpreted as an array index, `arr[np.array(seq)]`, which will result either in an error or a different result.
return np.add.reduce(sorted[indexer] * weights, axis=axis) / sumval
level
A 0.002168
B 0.008079
C 0.014878
D 0.055571
Name: bad_ind, dtype: float64