设:

\(p: 4\mid x\)

\(q: 100\mid x\)

\(r: 400\mid x\)

易知答案为

\[p\and\neg(q\and\neg r) \]

从而

#include <bits/stdc++.h>
using namespace std;
int main()
{
	int x;
	scanf("%d", &x);
	int p, q, r;
	p = (x % 4 == 0);
	q = (x % 100 == 0);
	r = (x % 400 == 0);
	
	printf("%d", p&&(!(q&&!r)));
	return 0;
}