本文学习自 狄泰软件学院 唐佐林老师的 C++课程
实验1：通过实现 Add() 实现复数相加
实验2: 操作符重载实验
实验3：将操作符重载定义为类的成员函数，编译器优先在成员函数中寻找操作符重载函数
实验1：通过实现 Add() 实现复数相加
#include <stdio.h>
class Complex
{
int a;
int b;
public:
Complex(int a = 0, int b = 0)
{
this->a = a;
this->b = b;
}
int getA()
{
return a;
}
int getB()
{
return b;
}
friend Complex Add(const Complex& p1, const Complex& p2);
};
Complex Add(const Complex& p1, const Complex& p2)
{
Complex ret;
ret.a = p1.a + p2.a;
ret.b = p1.b + p2.b;
return ret;
}
int main()
{
Complex c1(1, 2);
Complex c2(3, 4);
Complex c3 = Add(c1, c2); // c1 + c2
printf("c3.a = %d, c3.b = %d\n", c3.getA(), c3.getB());
return 0;
}
mhr@ubuntu:~/work/c++$
mhr@ubuntu:~/work/c++$ g++ 30-1.cpp
mhr@ubuntu:~/work/c++$ ./a.out
c3.a = 4, c3.b = 6
mhr@ubuntu:~/work/c++$
实验2: 操作符重载实验
#include <stdio.h>
class Complex
{
int a;
int b;
public:
Complex(int a = 0, int b = 0)
{
this->a = a;
this->b = b;
}
int getA()
{
return a;
}
int getB()
{
return b;
}
friend Complex operator + (const Complex& p1, const Complex& p2);
};
Complex operator + (const Complex& p1, const Complex& p2)
{
Complex ret;
ret.a = p1.a + p2.a;
ret.b = p1.b + p2.b;
return ret;
}
int main()
{
//构造对象
Complex c1(1, 2);
Complex c2(3, 4);
//调用操作符重载函数
Complex c3 = c1 + c2; // operator + (c1, c2)
printf("c3.a = %d, c3.b = %d\n", c3.getA(), c3.getB());
return 0;
}
mhr@ubuntu:~/work/c++$
mhr@ubuntu:~/work/c++$ g++ 30-2.cpp
mhr@ubuntu:~/work/c++$
mhr@ubuntu:~/work/c++$ ./a.out
c3.a = 4, c3.b = 6
mhr@ubuntu:~/work/c++$
mhr@ubuntu:~/work/c++$
实验3：将操作符重载定义为类的成员函数，编译器优先在成员函数中寻找操作符重载函数
#include <stdio.h>
class Complex
{
int a;
int b;
public:
Complex(int a = 0, int b = 0)
{
this->a = a;
this->b = b;
}
int getA()
{
return a;
}
int getB()
{
return b;
}
/*
参数是右操作数
左操作数为 this 参数，当前对象
*/
Complex operator + (const Complex& p)
{
Complex ret;
printf("Complex operator + (const Complex& p)\n");
ret.a = this->a + p.a;
ret.b = this->b + p.b;
return ret;
}
friend Complex operator + (const Complex& p1, const Complex& p2);
};
Complex operator + (const Complex& p1, const Complex& p2)
{
Complex ret;
printf("Complex operator + (const Complex& p1, const Complex& p2)\n");
ret.a = p1.a + p2.a;
ret.b = p1.b + p2.b;
return ret;
}
int main()
{
Complex c1(1, 2);
Complex c2(3, 4);
Complex c3 = c1 + c2; // c1.operator + (c2)
printf("c3.a = %d, c3.b = %d\n", c3.getA(), c3.getB());
return 0;
}
mhr@ubuntu:~/work/c++$
mhr@ubuntu:~/work/c++$ g++ 30-3.cpp
mhr@ubuntu:~/work/c++$ ./a.out
Complex operator + (const Complex& p)
c3.a = 4, c3.b = 6
mhr@ubuntu:~/work/c++$