/*

 * @lc app=leetcode.cn id=344 lang=c

 *

 * [344] 反转字符串

 *

 * https://leetcode-cn.com/problems/reverse-string/description/

 *

 * algorithms

 * Easy (65.20%)

 * Total Accepted:    39.8K

 * Total Submissions: 61.1K

 * Testcase Example:  '["h","e","l","l","o"]'

 *

 * 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

 *

 * 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

 *

 * 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

 *

 *

 *

 * 示例 1：

 *

 * 输入：["h","e","l","l","o"]

 * 输出：["o","l","l","e","h"]

 *

 *

 * 示例 2：

 *

 * 输入：["H","a","n","n","a","h"]

 * 输出：["h","a","n","n","a","H"]

 *

 */

void reverseString(char* s, int sSize) {

    int i,j=sSize-;

    char temp;

    for(i=;i<j;i++){

        temp = s[i];

        s[i] = s[j];

        s[j] = temp;

        j--;

    }

    return s;

}

#

# @lc app=leetcode.cn id=344 lang=python3

#

# [344] 反转字符串

#

# https://leetcode-cn.com/problems/reverse-string/description/

#

# algorithms

# Easy (65.20%)

# Total Accepted:    39.8K

# Total Submissions: 61.1K

# Testcase Example:  '["h","e","l","l","o"]'

#

# 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

#

# 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

#

# 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

#

#

#

# 示例 1：

#

# 输入：["h","e","l","l","o"]

# 输出：["o","l","l","e","h"]

#

#

# 示例 2：

#

# 输入：["H","a","n","n","a","h"]

# 输出：["h","a","n","n","a","H"]

#

#

class Solution:

    def reverseString(self, s: List[str]) -> None:

        """

        Do not return anything, modify s in-place instead.

        """

        s.reverse()