rm(list = ls()) library(car) library(MASS) library(openxlsx) A = read.xlsx("data141.xlsx") head(A)
fm = lm(y~x1+x2+x3+x4 , data=A ) #判断多重共线性 vif(fm)
> vif(fm) x1 x2 x3 x4 38.49621 254.42317 46.86839 282.51286 #具有多重共线性
#进行主成分回归 A.pr = princomp(~x1+x2+x3+x4 , data = A,cor=T) summary(A.pr,loadings = T) #输出特征值和特征向量
> summary(A.pr,loadings = T) #输出特征值和特征向量 Importance of components: Comp.1 Comp.2 Comp.3 Comp.4 Standard deviation 1.495227 1.2554147 0.43197934 0.0402957285 Proportion of Variance 0.558926 0.3940165 0.04665154 0.0004059364 Cumulative Proportion 0.558926 0.9529425 0.99959406 1.0000000000 Loadings: Comp.1 Comp.2 Comp.3 Comp.4 x1 0.476 0.509 0.676 0.241 x2 0.564 -0.414 -0.314 0.642 x3 -0.394 -0.605 0.638 0.268 x4 -0.548 0.451 -0.195 0.677
pre = predict(A.pr) #主成分,组合向量,无实际意义 A$z1 = pre[,1] A$z2 = pre[,2] #根据累积贡献率,根据保留两个主成分变量
lm.sol = lm(y~z1 + z2,data = A) #与主成分预测变量线性回归 lm.sol
> lm.sol Call: lm(formula = y ~ z1 + z2, data = A) Coefficients: (Intercept) z1 z2 95.4231 9.4954 -0.1201
> summary(lm.sol) #模型详细 Call: lm(formula = y ~ z1 + z2, data = A) Residuals: Min 1Q Median 3Q Max -3.3305 -2.1882 -0.9491 1.0998 4.4251 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 95.4231 0.8548 111.635 < 2e-16 *** z1 9.4954 0.5717 16.610 1.31e-08 *** z2 -0.1201 0.6809 -0.176 0.864 --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1 Residual standard error: 3.082 on 10 degrees of freedom Multiple R-squared: 0.965, Adjusted R-squared: 0.958 F-statistic: 138 on 2 and 10 DF, p-value: 5.233e-08
beta = coef(lm.sol) #主成分分析的预测变量的系数 beta
> beta (Intercept) z1 z2 95.4230769 9.4953702 -0.1200892
#预测变量还原 eigen_vec = loadings(A.pr) #特征向量 x.bar = A.pr$center #均值? x.sd = A.pr$scale #标准误? xishu_1 = (beta[2]*eigen_vec[,1])/x.sd xishu_2 = (beta[3]*eigen_vec[,2])/x.sd coef = xishu_1 + xishu_2 coef beta0 = beta[1] - sum(x.bar*coef) B = c(beta0,coef) B #还原后的回归系数
#岭估计 esti_ling = lm.ridge(y~x1+x2+x3+x4 , data = A, lambda = seq(0,15,0.01)) plot(esti_ling)
#取k=5 k = 5 X = cbind(1,as.matrix(A[,2:5])) y = A[,6] B_ = solve((t(X)%*%X) + k*diag(5))%*%t(X)%*%y B_
> B_ [,1] 0.06158362 x1 2.12614307 x2 1.16796919 x3 0.71043177 x4 0.49566883