我是Java和junit的新手.我有以下要测试的代码.如果你能发表关于测试它的最佳方法的想法,我将不胜感激.
基本上,以下代码是关于从群集中选择领导者.领导者持有对共享缓存的锁定,并且领导者的服务得到恢复和处置,如果它以某种方式失去对缓存的锁定.
我如何确保一个领导者/线程仍然保持对缓存的锁定,并且另一个线程在第一个执行时无法恢复其服务?
public interface ContinuousService {
public void resume();
public void pause();
}
public abstract class ClusterServiceManager {
private volatile boolean leader = false;
private volatile boolean electable = true;
private List<ContinuousService> services;
protected synchronized void onElected() {
if (!leader) {
for (ContinuousService service : services) {
service.resume();
}
leader = true;
}
}
protected synchronized void onDeposed() {
if (leader) {
for (ContinuousService service : services) {
service.pause();
}
leader = false;
}
}
public void setServices(List<ContinuousService> services) {
this.services = services;
}
@ManagedAttribute
public boolean isElectable() {
return electable;
}
@ManagedAttribute
public boolean isLeader() {
return leader;
}
public class TangosolLeaderElector extends ClusterServiceManager implements Runnable {
private static final Logger log = LoggerFactory.getLogger(TangosolLeaderElector.class);
private String election;
private long electionWaitTime= 5000L;
private NamedCache cache;
public void start() {
log.info("Starting LeaderElector ({})",election);
Thread t = new Thread(this, "LeaderElector ("+election+")");
t.setDaemon(true);
t.start();
}
public void run() {
// Give the connection a chance to start itself up
try {
Thread.sleep(1000);
} catch (InterruptedException e) {}
boolean wasElectable = !isElectable();
while (true) {
if (isElectable()) {
if (!wasElectable) {
log.info("Leadership requested on election: {}",election);
wasElectable = isElectable();
}
boolean elected = false;
try {
// Try and get the lock on the LeaderElectorCache for the current election
if (!cache.lock(election, electionWaitTime)) {
// We didn't get the lock. cycle round again.
// This code to ensure we check the electable flag every now & then
continue;
}
elected = true;
log.info("Leadership taken on election: {}",election);
onElected();
// Wait here until the services fail in some way.
while (true) {
try {
Thread.sleep(electionWaitTime);
} catch (InterruptedException e) {}
if (!cache.lock(election, 0)) {
log.warn("Cache lock no longer held for election: {}", election);
break;
} else if (!isElectable()) {
log.warn("Node is no longer electable for election: {}", election);
break;
}
// We're fine - loop round and go back to sleep.
}
} catch (Exception e) {
if (log.isErrorEnabled()) {
log.error("Leadership election " + election + " failed (try bfmq logs for details)", e);
}
} finally {
if (elected) {
cache.unlock(election);
log.info("Leadership resigned on election: {}",election);
onDeposed();
}
// On deposition, do not try and get re-elected for at least the standard wait time.
try { Thread.sleep(electionWaitTime); } catch (InterruptedException e) {}
}
} else {
// Not electable - wait a bit and check again.
if (wasElectable) {
log.info("Leadership NOT requested on election ({}) - node not electable",election);
wasElectable = isElectable();
}
try {
Thread.sleep(electionWaitTime);
} catch (InterruptedException e) {}
}
}
}
public void setElection(String election) {
this.election = election;
}
@ManagedAttribute
public String getElection() {
return election;
}
public void setNamedCache(NamedCache nc) {
this.cache = nc;
}
解决方法:
作为测试框架的替代方法(或者在JUnit之上的额外扩展,如果你使用它)只是一些简单的旧代码:
>创建多个线程并将它们应用于此例程.
>遍历线程并测试每个线程,直到找出谁是领导者.
>将不同的环境变化(包括时间的推移)应用到程序的状态并重新进行测试.领导者仍然是领导者吗?
>现在,强迫领导者退位(杀死那个线索或其他东西).另一个线程接管了吗?