个人答案：

①

#include <iostream>
using namespace std;
int main()
{
    int n[5] = { 8, 6, 5, 4, 1 };
    int i, j, temp;
    for (i = 0, cout << "原始排序为: "; i < 5; cout << n[i++] << ' ');
    //进行累加依次排序输出
    for (i = 0, j = 4; i < 5 / 2; temp = n[i], n[i] = n[j], n[j] = temp, i++, j--);
    //设置中间变量temp进行置换
    for (i = 0, cout << "\n新排序为: "; i < 5; cout << n[i++] << ' ');
    cout << endl;
    system("pause");
    return 0;
}

②

#include <iostream>
using namespace std;
int main()
{
 int n[5] = { 8, 6, 5, 4, 1 };//确定初始数组
 int i, j, t;
 cout << "初始数组: ";
 for (i = 0; i < 5;)
 {
  cout << n[i++] << ' ';
 }           //输出初始数组
 for (i = 0, j = 4; i <= 2; i++, j--)
 {
  t = n[i];
  n[i] = n[j];
  n[j] = t;
 }            //交换初始数组内数的排序
 cout << "\n逆序数组: ";
 for (i = 0;i < 5; )
 {
  cout << n[i++] << ' ';
 }          //交换后的数组输出
 cout << endl;
 system("pause");
 return 0;
}

结果（其一）：

 参考答案：

#include <iostream>

using namespace std;

int main()

{ const int n=5;

int a[n],i,temp;

cout<<"enter array a:"<<endl;

for (i=0;i<n;i++)

cin>>a[i];

cout<<"array a:"<<endl;

for (i=0;i<n;i++)

cout<<a[i]<<" ";

for (i=0;i<n/2;i++) //循环的作用是将对称的元素的值互换

{ temp=a[i];

a[i]=a[n-i-1];

a[n-i-1]=temp;

}

cout<<endl<<"Now,array a:"<<endl;

for (i=0;i<n;i++)

cout<<a[i]<<" ";

cout<<endl;return 0;

}