我的目标是获取XML字符串并使用XMLBeans XmlObject解析它并添加一些子节点.

这是一个示例文档(xmlString),

<?xml version="1.0"?>
<rootNode>
 <person>
  <emailAddress>joefoo@example.com</emailAddress>
 </person>
</rootNode>

这是添加一些节点后我想要XML文档的方式,

<?xml version="1.0"?>
<rootNode>
 <person>
  <emailAddress>joefoo@example.com</emailAddress>
  <phoneNumbers>
   <home>555-555-5555</home>
   <work>555-555-5555</work>
  <phoneNumbers>
 </person>
</rootNode>

基本上,只需添加< phoneNumbers />具有两个子节点的节点< home />和< work />.

就我而言,

XmlObject xml = XmlObject.Factory.parse(xmlString);

谢谢

解决方法:

XMLBeans似乎很麻烦,这是使用XOM的解决方案：

import nu.xom.*;

Builder = new Builder();
Document doc = builder.build(new java.io.StringBufferInputStream(inputXml));
Nodes nodes = doc.query("person");
Element homePhone = new Element("home");
homePhone.addChild(new Text("555-555-5555"));
Element workPhone = new Element("work");
workPhone.addChild(new Text("555-555-5555"));
Element phoneNumbers = new Element("phoneNumbers");
phoneNumbers.addChild(homePhone);
phoneNumbers.addChild(workPhone);
nodes[0].addChild(phoneNumbers);
System.out.println(doc.toXML()); // should print modified xml