Description
Edward, a poor copy typist, is a user of the Dvorak Layout. But now he has only a QWERTY Keyboard with a broken Caps Lock key, so Edward never presses the broken Caps Lock key. Luckily, all the other keys on the QWERTY keyboard work well. Every day, he has a lot of documents to type. Thus he needs a converter to translate QWERTY into Dvorak. Can you help him?
The QWERTY Layout and the Dvorak Layout are in the following:
| The QWERTY Layout |
|---|
|
|
| The Dvorak Layout |
|---|
|
|
Input
A QWERTY document Edward typed. The document has no more than 100 kibibytes. And there are no invalid characters in the document.
Output
The Dvorak document.
Sample Input
Jgw Gqm Andpw a H.soav Patsfk f;doe
Nfk Gq.d slpt a X,dokt vdtnsaohe
Kjd yspps,glu pgld; aod yso kd;kgluZ
1234567890
`~!@#$%^&*()}"']_+-=ZQqWEwe{[\|
ANIHDYf.,bt/
ABCDEFuvwxyz
Sample Output
Hi, I'm Abel, a Dvorak Layout user.
But I've only a Qwerty keyboard.
The following lines are for testing:
1234567890
`~!@#$%^&*()+_-={}[]:"'<>,.?/\|
ABCDEFuvwxyz
AXJE>Ugk,qf;
#include<iostream>
#include<algorithm>
#include<map>
using namespace std;
map<char,char>M;
void init(){
M['-']='['; M['A']='A'; M['X']='Q';
M['_']='{'; M['a']='a'; M['x']='q';
M['+']='}'; M['s']='o'; M['C']='J';
M['=']=']'; M['S']='O'; M['c']='j';
M['Q']='"'; M['D']='E'; M['V']='K';
M['q']='\''; M['d']='e'; M['v']='k';
M['W']='<'; M['F']='U'; M['B']='X';
M['w']=','; M['f']='u'; M['b']='x';
M['E']='>'; M['G']='I'; M['N']='B';
M['e']='.'; M['g']='i'; M['n']='b';
M['R']='P'; M['H']='D'; M['M']='M';
M['r']='p'; M['h']='d'; M['m']='m';
M['T']='Y'; M['j']='h'; M['<']='W';
M['t']='y'; M['K']='T'; M[',']='w';
M['Y']='F'; M['J']='H'; M['>']='V';
M['y']='f'; M['k']='t'; M['.']='v';
M['U']='G'; M['L']='N'; M['?']='Z';
M['u']='g'; M['l']='n'; M['/']='z';
M['I']='C'; M[':']='S'; M['{']='?';
M['i']='c'; M[';']='s'; M['[']='/';
M['O']='R'; M['"']='_'; M['}']='+';
M['o']='r'; M['\'']='-'; M[']']='=';
M['P']='L'; M['Z']=':';
M['p']='l'; M['z']=';';
}
int main(){
init();
string str;
while(getline(cin,str)){
for(int i=;i<str.length();i++){
if(M.count(str[i]))cout<<M[str[i]];
else cout<<str[i];
}
cout<<endl;
}
return ;
}