我在我的本机项目中使用react-navigation来处理导航和路线.
就我而言,我有一个ViewA和一个ViewB.
ViewA需要我在ViewB中填写的信息.
用户流是ViewA-> ViewB-> ViewA.
** VIEW A **
import React from "react";
import { Button, Text, View } from "react-native";
class ViewA extends React.Component {
state = { selected: false };
onSelect = data => {
this.setState(data);
};
onPress = () => {
this.props.navigate("ViewB", { onSelect: this.onSelect });
};
render() {
return (
<View>
<Text>{this.state.selected ? "Selected" : "Not Selected"}</Text>
<Button title="Next" onPress={this.onPress} />
</View>
);
}
}
.
**VIEW B**
import React from "react";
import { Button } from "react-native";
class ViewB extends React.Component {
goBack() {
const { navigation } = this.props;
navigation.goBack();
navigation.state.params.onSelect({ selected: true });
}
render() {
return <Button title="back" onPress={this.goBack} />;
}
}
我想做的是:我不想从左到右打开ViewB,而是希望它从下到上(在ViewA上方)打开,并具有一个紧密的“上下”过渡.如模态.
我的问题是,我想保持我的StackNavigator不变.并希望自定义此过渡.
我不要模态
感谢您的时间和帮助
解决方法:
确保将其导入到页面顶部
import CardStackStyleInterpolator from "react-navigation/src/views/CardStack/CardStackStyleInterpolator";
对于简单的过渡,这就是您的导航器的外观.
StackNavigator(
{
Scenes...
},
{
transitionConfig: () => ({
screenInterpolator: props => {
// Basically you need to create a condition for individual scenes
if (props.scene.route.routeName === 'NameOfOneScene') {
// forVertical makes the scene transition for Top to Bottom
return CardStackStyleInterpolator.forVertical(props);
}
const last = props.scenes[props.scenes.length - 1];
// This controls the transition when navigation back toa specific scene
if (last.route.routeName === 'NameOfOneScene') {
// Here, forVertical flows from Top to Bottom
return CardStackStyleInterpolator.forVertical(props);
}
This declares the default transition for every other scene
return CardStackStyleInterpolator.forHorizontal(props);
},
navigationOptions: {
...
},
cardStyle: {
...
}
}