自动化点检selenium今天碰到一个需求,定义一个函数,需要返回【现在时间+2分钟】的时间,整理如下,顺便温习下格式化时间
import datetime # 日期时间加2分钟 def date_input_add_2(by, locator): try: t = (datetime.datetime.now() + datetime.timedelta(minutes=2)).strftime("%Y-%m-%d %H:%M") input_value(by, locator, t) except Exception as e: raise e
当前日期时间
import datetime print datetime.datetime.now() # 2018-05-08 16:53:30.101000
格式化时间
import datetime print datetime.datetime.now().strftime("%Y-%m-%d %H:%M") # 2018-05-08 16:54
多加一天
import datetime print (datetime.datetime.now()+datetime.timedelta(days=1)).strftime("%Y-%m-%d %H:%M:%S") # 2018-05-09 16:56:07
减一天
import datetime print (datetime.datetime.now()+datetime.timedelta(days=-1)).strftime("%Y-%m-%d %H:%M:%S") # 2018-05-07 16:56:59
其他类似
import datetime in_date = '2016-08-31' dt = datetime.datetime.strptime(in_date, "%Y-%m-%d") out_date = (dt + datetime.timedelta(days=2)).strftime("%Y-%m-%d") print(out_date) # 2016-09-02
可以把days改为hours minutes,就可以提前XX小时/分钟了。
timedelta([days[, seconds[, microseconds[, milliseconds[, minutes[, hours[, weeks]]]]]]])
减去一年
import datetime from dateutil.relativedelta import relativedelta d = datetime.datetime.strptime('20180131', '%Y%m%d') print(d) // 2018-01-31 00:00:00 print((d - relativedelta(years=1)).strftime('%Y%m%d')) // 20170131
还可以把years
改为months
时区转换
from datetime import datetime from datetime import timezone from datetime import timedelta # 世界标准时间 utc_time = datetime(2019, 7, 30, 7, 50, 0) # 北京时间UTC+8 cst_time =utc_time.astimezone(timezone(timedelta(hours=-8))).strftime("%Y-%m-%d %H:%M:%S")
原文:https://blog.csdn.net/lilongsy/article/details/80242427