多线程:head first Thread.join()

不使用Thread.join() 测试线程

先上代码:

/**
* Created by Zero on 2017/8/23.
*/
public class TestJoin implements Runnable {
public static int a = 0; @Override
public void run() {
for (int i = 0; i < 5; i++) {
a = a + 1;
}
} public static void main(String[] args) throws InterruptedException {
TestJoin j = new TestJoin();
Thread thread = new Thread(j);
thread.start();
System.out.println(a);
}
}

以上示例会输出5吗?可能性不大,有可能永远输出为0,之前在线程池原理的那篇就提到过,线程的启动和销毁都需要时间,此处因为thread还没启动好,或者正在为它分配资源准备运行,就已经执行完输出了。

怎样才能确保每次都能输出5呢?现在有请我们的主角join方法闪亮登场,代码如下:

/**
* Created by apple on 2017/8/23.
*/
public class TestJoin implements Runnable {
public static int a = 0; @Override
public void run() {
for (int i = 0; i < 5; i++) {
a = a + 1;
}
} public static void main(String[] args) throws InterruptedException {
TestJoin j = new TestJoin();
Thread thread = new Thread(j);
thread.start();
/**
* 测试join方法的作用,与下面的threadAgain线程作对比。
*/
thread.join();
System.out.println(a);
a = 0;
Thread threadAgain = new Thread(j);
threadAgain.start();
System.out.println(a);
}
}

输出的结果将是5和0。

Thread.join()作用

Thread.join(),之前看资料的时候,有些人说可以理解成“将两个线程合并成一个线程”,我是觉得这样说是很不科学的,虽然这样通俗易懂,但这确实是两个不同的线程,只是在调用Thread.join()后,会先执行完Thread线程后再去执行当前线程,即上述的在主线程中执行到thread.join();后,先去执行thread,直到thread执行完后再去执行主线程。

测试Thread.join(long millis)

/**
* Created by apple on 2017/8/23.
*/
public class TestJoin implements Runnable {
public static int a = 0; @Override
public void run() {
for (int i = 0; i < 5; i++) {
a = a + 1;
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
} public static void main(String[] args) throws InterruptedException {
TestJoin j = new TestJoin();
Thread thread = new Thread(j);
thread.start();
/**
* 测试join方法的作用
*/
thread.join(3000);
System.out.println("thread线程结果为:"+a);
a = 0;
Thread threadAgain = new Thread(j);
threadAgain.start();
System.out.println("threadAgain线程结果为:"+a);
}
}

输出:

thread线程结果为:3
threadAgain线程结果为:0

先上一段源码再来分析:

/**
* Waits at most {@code millis} milliseconds for this thread to
* die. A timeout of {@code 0} means to wait forever.
*
* <p> This implementation uses a loop of {@code this.wait} calls
* conditioned on {@code this.isAlive}. As a thread terminates the
* {@code this.notifyAll} method is invoked. It is recommended that
* applications not use {@code wait}, {@code notify}, or
* {@code notifyAll} on {@code Thread} instances.
*
* @param millis
* the time to wait in milliseconds
*
* @throws IllegalArgumentException
* if the value of {@code millis} is negative
*
* @throws InterruptedException
* if any thread has interrupted the current thread. The
* <i>interrupted status</i> of the current thread is
* cleared when this exception is thrown.
*/
public final synchronized void join(long millis)
throws InterruptedException {
long base = System.currentTimeMillis();
long now = 0; if (millis < 0) {
throw new IllegalArgumentException("timeout value is negative");
} if (millis == 0) {
while (isAlive()) {
wait(0);
}
} else {
while (isAlive()) {
long delay = millis - now;
if (delay <= 0) {
break;
}
wait(delay);
now = System.currentTimeMillis() - base;
}
}
}

多线程:head first Thread.join()

源码爸爸说了,孩子,我给你millis这么长的时间,能不能完成任务那是你的事情了,能提前完成,咱就提前走下去,不能完成,过期不候,自己看着办吧。

默认情况下,Thread.join()即Thread.join(0),当为0的时候,那才叫真爱呢,线程会一直等下去,知道执行结束为止,才会继续朝下执行。

isAlive():用来测试线程是否处于活动状态,相当于 run 是否还在执行。

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