C++实现递归版二分搜索算法

无聊撸了一个,没啥技术含量,别吐槽。。

#include <iostream>
using namespace std;
int BinarySearch(int* nums,int key,int len);
int search(int* nums,int key,int L,int R); int main()
{
int *nums;
int length;
int keyNum;
cout<<"请输入你希望的数字个数:"<<endl;
cin>>length;
nums = new int[length];
cout<<"请输入"<<length<<"个数:"<<endl;
for(int i=0;i<length;i++)
scanf("%d",&nums[i]);
cout<<"输入你想找的数字::"<<endl;
while(cin>>keyNum){
int result = BinarySearch(nums,keyNum,length);
if(!(result==-1))
cout<<"Position in array is: "<<result<<"\n"<<endl;
else
cout<<"Failed!"<<endl;
delete[] nums;
cout<<"请输入你希望的数字个数:"<<endl;
cin>>length;
nums = new int[length];
cout<<"请输入"<<length<<"个数:"<<endl;
for(int i=0;i<length;i++)
scanf("%d",&nums[i]);
cout<<"输入你想找的数字::"<<endl;
}
return 0;
} int BinarySearch(int* nums,int key,int len){ //仅作为用户入口
return search(nums,key,0,len);
} int search(int* nums,int key,int L,int R){
int mid = (L+R)/2;
if(nums[mid]==key) return mid; //递归基
if(nums[mid]>key)
return search(nums,key,L,mid-1);
else if(nums[mid]<key)
return search(nums,key,mid+1,R);
return -1; //如果失败了返回-1
}

OVER

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