mysql 数据表中查找、删除重复记录

为了性能考虑,在阅读之前提醒大家,如果有子查询,子查询查询到的数据最好不要超过总数据量的30%。

查询有重复数据的记录
select * from F group by a,b,c,d having count(*)>1

select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
SQL删除重复数据方法
例如: 
id           name         value
1 a pp
2 a pp
3 b iii
4 b pp
5 b pp
6 c pp
7 c pp
8 c iii
id是主键 
要求得到这样的结果 
id           name         value
1 a pp
3 b iii
4 b pp
6 c pp
8 c iii

方法1

delete   YourTable    where   [id]   not   in   (  select   max([id])   from   YourTable    group   by   (name   +   value))

方法2

delete   a  from   表   a   left   join(  select   id=min(id)   from   表   group   by   name,value  )b   on   a.id=b.id  where   b.id   is   null

查询及删除重复记录的SQL语句 查询及删除重复记录的SQL语句

1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断

select * from people where peopleId in (select   peopleId from   people group by   peopleId having count(peopleId) > 1)

2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录

delete from people where peopleId in (select   peopleId from people group by   peopleId   having count(peopleId) > 1) and rowid not in (select min(rowid) from   people group by peopleId having count(peopleId )>1)

3、查找表中多余的重复记录(多个字段)

select * from vitae a where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录

delete from vitae a where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录

select * from vitae a where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

(二)

比方说 在A表中存在一个字段“name”, 而且不同记录之间的“name”值有可能会相同, 现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;

Select Name,Count(*) From A Group By Name Having Count(*) > 1 如果还查性别也相同大则如下: Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

(三)

方法一

declare @max integer,@id integer declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1 open cur_rows fetch cur_rows into @id,@max while @@fetch_status=0 begin select @max = @max -1 set rowcount @max delete from 表名 where 主字段 = @id fetch cur_rows into @id,@max end close cur_rows set rowcount 0

方法二

"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。   

1、对于第一种重复,比较容易解决,使用 select distinct * from tableName   就可以得到无重复记录的结果集。   如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除

select distinct * into #Tmp from tableName drop table tableName select * into tableName from #Tmp drop table #Tmp   

发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。   

2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下   假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集

select identity(int,1,1) as autoID, * into #Tmp from tableName select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID select * from #Tmp where autoID in(select autoID from #tmp2)  

 最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)

(四) 查询重复

select * from tablename where id in ( select id from tablename group by id having count(id) > 1 )

去重:

-- //////////////////////////////////实现1
DELETE
FROM
tableName
WHERE
id NOT IN (
SELECT
*
FROM
(
SELECT
min(t3.id)
FROM
tableName t3
GROUP BY
column1(即去重的字段)
) t2
) -- //////////////////////////////////实现2
DELETE
FROM
tableName t1
WHERE
t1.id NOT IN (
SELECT
*
FROM
(
SELECT DISTINCT
id
FROM
tableName t3
) t2
)
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