数据结构(C语言)--链表

线性表的链式实现


主要内容:

包含链表的创建、增、删、改、查操作

代码实现:

以下学生信息为例实现代码


#include<stdio.h>
#include<stdlib.h>
#include<string.h>

struct student *create(struct student *);//创建链表      
void  name_found(struct student *);      //根据姓名进行查找,返回此学生的学号和成绩 
void  position_found(struct student *);  //根据指定的位置可返回相应的学生信息(学号,姓名) 
void  insert_position(struct student*);  //给定一个学生信息,插入到表中指定的位置
void  del_position(struct student*);     //删除指定位置的学生记录
void  statistic_student(struct student*);//统计表中学生个数

struct student
{
	char  num[14];     //学号
	char  name[20];    //姓名
	int   sex;         //性别
	char  tel[14];     //联系电话
	char  qq[12];      //QQ号
	struct student *next;
}; 

int main()
{
	struct student *head=NULL,*p,*p1; 
	head=create(head);
	p=head;
	while(p!=NULL)
	{
		printf("%10s%10d%15s%15s%10s\n",p->name,p->sex,p->num,p->tel,p->qq);//打印链表信息 
		p=p->next;
	}
    printf("\n");
    printf("根据姓名查找输出赵括的信息\n");
    name_found(head);
    printf("\n");
    printf("输出指定位置信息第二位同学的信息\n");
    position_found(head);                                              //输出指定位置的信息 
    printf("\n");
    printf("将刘刚的信息插入到第二位后:\n"); 
    insert_position(head);
    printf("\n");
    printf("删除第三位同学的信息后:\n");
    del_position(head);
    printf("\n");
    statistic_student(head);
    printf("\n");
	return 0;
}

struct student *create(struct student * head)
{
	struct student *p1,*p2,*p3,*p4;
	
	p1=(struct student *)malloc(sizeof(struct student));       //信息1 
	strcpy(p1->name,"李思"  );
	p1->sex=0;
	strcpy(p1->num,"2013002");
	strcpy(p1->tel,"13910121978");
	strcpy(p1->qq,"8796532");
	p1->next=NULL;
    
	p2=(struct student *)malloc(sizeof(struct student));       //信息2 
	strcpy(p2->name,"陈琪");
	p2->sex=1;
	strcpy(p2->num,"2013003");
	strcpy(p2->tel,"13789450012");
	strcpy(p2->qq,"3789123");
	p2->next=NULL;
	
	p3=(struct student *)malloc(sizeof(struct student));       //信息3 
	strcpy(p3->name,"王强");
	p3->sex=0;
	strcpy(p3->num,"2013004");
	strcpy(p3->tel,"13634567856");
	strcpy(p3->qq,"6543783");
	p3->next=NULL;
	
	p4=(struct student *)malloc(sizeof(struct student));       //信息4
	strcpy(p4->name,"赵括");
	p4->sex=1;
	strcpy(p4->num,"2013005");
	strcpy(p4->tel,"13534408976");
	strcpy(p4->qq,"5679");
	p4->next=NULL;
	
	head=p1; 
	p1->next=p2;
	p2->next=p3;
	p3->next=p4;
	p4->next=NULL;
	return head;
}

void name_found(struct student *r)          //根据姓名进行查找,返回此学生的学号和成绩  
{
	struct student *q;
	q=r;
	char name[20]="赵括"; 
	//scanf("%s",&name);
	while(q!=NULL)
	{
		if(strcmp(q->name,name)==0) 
		{
		printf("%10s%15s%15s\n",q->name,q->num,q->tel);break;
     	}
    	q=q->next;
	}
}

void  position_found(struct student *a)      //根据指定的位置可返回相应的学生信息(学号,姓名) 
{
	struct student *b;
	int m=2;
    //scanf("%d",&m);
	int i=0;
	b=a;
	while(b!=NULL)
	{
     i++;
     while(i==m)
     {
     	printf("%10s%15s\n",b->name,b->num);break;
	 }
	 b=b->next;
	}
}
void  insert_position(struct student *pa)     //给定一个学生信息,插入到表中指定的位置
{
	struct student *pb,*pc;
	int i=1;
	int n=2;                                  //将刘刚的信息插入到第2个 
	//printf("请输入插入的点"); 
	//scanf("%d",&n);
	pb=pa;
	while(pb!=NULL&&i<n-1)
	{
		i++;
		pb=pb->next;
	}
     pc=(struct student *)malloc(sizeof(struct student));
     strcpy(pc->name,"刘刚");
     pc->sex=1;
     strcpy(pc->num,"2013006");
     strcpy(pc->tel,"13386543211");
     strcpy(pc->qq,"98315");
     
	 pc->next=pb->next;
     pb->next=pc;
     //pb=pa;
     while(pb!=NULL)
	{
		printf("%10s%10d%15s%15s%10s\n",pb->name,pb->sex,pb->num,pb->tel,pb->qq);   //打印链表信息 
		pb=pb->next;
	}
}
void  del_position(struct student *t)
 {
 	struct student *l,*k;
 	int i=1;
 	int n=3;
	 //printf("请输入想删除的点");
	 //scanf("%d",&n);                                                //删除第3位同学的信息 
 	l=t;
 	while(l!=NULL&&i<n-1)
 	{
 		l=l->next;
 		i++;
	 }
	 k=l->next;
	 l->next=k->next;
	 free(k);
	 l=t;
	 while(l!=NULL)
	{
		printf("%10s%10d%15s%15s%10s\n",l->name,l->sex,l->num,l->tel,l->qq);   //打印链表信息 
		l=l->next;
	}
 }
void  statistic_student(struct student*y)    //统计表中学生个数
 {
 	int i=0;
 	struct student *x;
 	x=y;
 	while(x!=NULL)
 	{
 		i++;
 		x=x->next;
	 }
	 printf("学生总数为:%d\n",i);
 }
 
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