'''
求字符串"dfjkfjeijdkf" 计算个数为1字符及其下标
'''

def str_single(string):

    a={}
    for n,i in enumerate(string,0):
        if i not in a:
            a[i]=[n]

        else:
            a[i].append(n)

    result = {}
    for i,j in a.items():
        if len(j) == 1:
            result[i] = j[0]

    return result
print(str_single("adsax"))