http://acm.hdu.edu.cn/showproblem.php?pid=2140
Problem Description
I believe many people are the fans of * break. How clever Michael is!! In order that the message won't be found by FBI easily, he usually send code letters to Sara by a paper crane. Hence, the paper crane is Michael in the heart of Sara. Now can you write a program to help Sara encode the letter from Michael easily?
The letter from Michael every time is a string of lowercase letters. You should encode letters as the rules below:
b is ' ', q is ',', t is '!', m is l, i is e, c is a, a is c, e is i, l is m. It is interesting. Are you found that it is just change michael to leahcim?
The letter from Michael every time is a string of lowercase letters. You should encode letters as the rules below:
b is ' ', q is ',', t is '!', m is l, i is e, c is a, a is c, e is i, l is m. It is interesting. Are you found that it is just change michael to leahcim?
Input
The input will consist of several cases, one per line.
Each case is a letter from Michael, the letteres won't exceed 10000.
Each case is a letter from Michael, the letteres won't exceed 10000.
Output
For each case, output the encode letter one line.
Sample Input
pmicsibforgevibliqbscrct
ebmovibyout
Sample Output
please forgive me, sara!
i love you!
代码：
#include <bits/stdc++.h>
using namespace std; const int maxn = 1e5 + 10;
char s[maxn];
char a[11]={'b', 'q', 't', 'm', 'i', 'c', 'a', 'e', 'l'};
char b[11]={' ', ',', '!', 'l', 'e', 'a', 'c', 'i', 'm'}; int main() {
while(~scanf("%s", s)) {
int len = strlen(s);
for(int i = 0; i < len; i ++) {
if(s[i] == 'b')
s[i] = ' ';
else if(s[i] == 't')
s[i] = '!';
else if(s[i] == 'm')
s[i] = 'l';
else if(s[i] == 'i')
s[i] = 'e';
else if(s[i] == 'c')
s[i] = 'a';
else if(s[i] == 'a')
s[i] = 'c';
else if(s[i] == 'e')
s[i] = 'i';
else if(s[i] == 'l')
s[i] = 'm';
else if(s[i] == 'q')
s[i] = ',';
} printf("%s\n", s);
}
return 0;
}