You are given two arrays A and B consisting
of integers, sorted in non-decreasing order. Check whether it is possible to choose knumbers
in array A and choose m numbers
in array B so that any number chosen in the first array is strictly less than any number chosen in the second array.

The first line contains two integers nA, nB (1 ≤ nA, nB ≤ 105),
separated by a space — the sizes of arrays A and B,
correspondingly.

The second line contains two integers k and m (1 ≤ k ≤ nA, 1 ≤ m ≤ nB),
separated by a space.

The third line contains nA numbers a1, a2, ... anA ( - 109 ≤ a1 ≤ a2 ≤ ... ≤ anA ≤ 109),
separated by spaces — elements of array A.

The fourth line contains nB integers b1, b2, ... bnB ( - 109 ≤ b1 ≤ b2 ≤ ... ≤ bnB ≤ 109),
separated by spaces — elements of array B.

Print "YES" (without the quotes), if you can choose k numbers
in array A and m numbers
in array B so that any number chosen in arrayA was
strictly less than any number chosen in array B. Otherwise, print "NO"
(without the quotes).

In the first sample test you can, for example, choose numbers 1 and 2 from array A and number 3 from array B (1
< 3 and 2 < 3).

In the second sample test the only way to choose k elements in the first array and m elements
in the second one is to choose all numbers in both arrays, but then not all the numbers chosen in A will be less than all the numbers
chosen in B: .

#include <iostream>

#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#include <algorithm>

using namespace std;

int a[100100],b[100010];

int n,m;

int k,t;

int main()

{

    while(scanf("%d%d",&n,&m)!=EOF)

    {

        scanf("%d%d",&k,&t);

        for(int i=0; i<n; i++)

        {

            scanf("%d",&a[i]);

        }

        for(int i=0; i<m; i++)

        {

            scanf("%d",&b[i]);

        }

        if(a[k-1] < b[m-t])

        {

            printf("YES\n");

        }

        else

        {

            printf("NO\n");

        }

    }

    return 0;

}