Say you have an array for which the ith element is the price of a given stock on day i.
If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit.
Example
Given array [3,2,3,1,2], return 1.
LeetCode上的原题，请参见我之前的解法Best Time to Buy and Sell Stock。
class Solution { public: /** * @param prices: Given an integer array * @return: Maximum profit */ int maxProfit(vector<int> &prices) { int res = 0, mn = INT_MAX; for (int i = 0; i < prices.size(); ++i) { mn = min(mn, prices[i]); res = max(res, prices[i] - mn); } return res; } };
本文转自博客园Grandyang的博客，原文链接：买卖股票的最佳时间[LintCode] Best Time to Buy and Sell Stock ，如需转载请自行联系原博主。