python day09作业答案

2.
def lst(input):
lst2=[]
count=0
for i in range(0,len(input)):
if i %2!=0:
lst2.append(input[i])
return lst2
a=lst((2,9,29,36,9))
print(a) 3.
def pd(input):
if len(input)>5:
return True
else:
return False
a=pd((5,5,6,9,7))
print(a) 4.
def a(input):
if type(input)==list:
if len(input)>2:
return input[0],input[1]
else:
return ('请输入列表')
d=a(['小明','大明'])
print(d)
5.写函数,计算传入函数的字符串中, 数字、字母、空格 以及 其他内容的个数,并返回结果。
def func(s=""): # function
shuzi = 0
zimu = 0
kongge = 0
qita = 0
for c in s: # 循环字符串.拿到每个字符
if c.isdigit(): # 数字
shuzi += 1
elif c.isalpha():
zimu+=1
elif c == ' ':
kongge += 1
else:
qita += 1
return shuzi, zimu, kongge, qita
6.
def num(n1,n2):
if n1>n2:
return n1
elif n1<n2:
return n2
a=num(26,98)
print(a)
7.
def dic(dic):
for k,v in dic.items():
if len(v)>2:
dic[k]=v[0:2]
return dic
a=dic({1:'dsfgasdf',2:'sdfsdsd',3:'卡卡卡的双丰收'})
print(a)
8.
def list(input):
dic={}
if type(input)==type([]):
for i in range(0,len(input)):
dic[i]=input[i]
return dic
elif type(input)!=type([]):
return '请输入列表'
a=list([2,3,6,5,9,8])
print(a)
9.
def xx(姓名=input('姓名:'),性别=input('性别:'),年龄=input('年龄:'),学历=input('学历:')):
student_msg={}
student_msg['姓名']=姓名
student_msg['性别'] = 性别
student_msg['年龄'] = 年龄
student_msg['学历'] = 学历
return student_msg
a=xx()
print(a)
9.
def func(name, age,edu,sex ="男"):
f = open("student.msg", mode="a", encoding="utf-8")
f.write(name+"_"+str(age)+"_"+sex+"_"+edu+"\n")
f.flush()
f.close()
10.
def xx():
while True:
a=input('姓名:')
if a.lower() == 'q':
break
else:
student_msg={}
student_msg['姓名']=a
student_msg['性别'] = input('性别:')
student_msg['年龄'] = input('年龄:')
student_msg['学历'] = input('学历:')
return student_msg aa=xx()
print(aa)
11.
def ch(wjm,ynr,xnr):
import os
with open(wjm,'r',encoding='utf-8') as f1, open('a.txt','w',encoding='utf-8') as f2:
for i in f1.readlines():
a=i.replace(ynr,xnr)
f2.write(a)
os.remove(wjm)
os.rename('a.txt',wjm)
ch('4.txt','alex','sb')
12.
def dl(username,password):
count=0
while count<=3:
if username=='' and password=='':
return ('登录成功')
count=count+1
else :
return ('请重新输入:')
count+=1 a=dl(12563,'')
print(a)
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