test

Stm+1=Stmexp((r−12σ2)(tm+1−tm)+σtm+1−tm−−−−−−−−√Zt)0≤tm≤tm+1≤T

Stm+1=Stmexp((r−12σ2)(tm+1−tm)+σtm+1−tm−−−−−−−−√Zt)0≤tm≤tm+1≤T

Stm+1=Stmexp((r−12σ2)(tm+1−tm)+σtm+1−tm−−−−−−−−√Zt)0≤tm≤tm+1≤T

Stm+1=Stmexp((r−12σ2)(tm+1−tm)+σtm+1−tm−−−−−−−−√Zt)0≤tm≤tm+1≤T

Stm+1=Stmexp((r−12σ2)(tm+1−tm)+σtm+1−tm−−−−−−−−√Zt)0≤tm≤tm+1≤T

Stm+1=Stmexp((r−12σ2)(tm+1−tm)+σtm+1−tm−−−−−−−−√Zt)0≤tm≤tm+1≤T

Stm+1=Stmexp((r−12σ2)(tm+1−tm)+σtm+1−tm−−−−−−−−√Zt)0≤tm≤tm+1≤T

Stm+1=Stmexp((r−12σ2)(tm+1−tm)+σtm+1−tm−−−−−−−−√Zt)0≤tm≤tm+1≤T

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