Question
Given two 1d vectors, implement an iterator to return their elements alternately.
For example, given two 1d vectors:
v1 = [1, 2]
v2 = [3, 4, 5, 6]
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1, 3, 2, 4, 5, 6].
Follow up: What if you are given k 1d vectors? How well can your code be extended to such cases?
Solution
This solution is suitable for k vectors.
public class ZigzagIterator {
private List<Iterator> list;
public ZigzagIterator(List<Integer> v1, List<Integer> v2) {
list = new ArrayList<Iterator>();
if (v1.iterator().hasNext())
list.add(v1.iterator());
if (v2.iterator().hasNext())
list.add(v2.iterator());
}
public int next() {
Iterator<Integer> current = list.remove(0);
int result = current.next();
if(current.hasNext())
list.add(current);
return result;
}
public boolean hasNext() {
return list.size() > 0 ? true : false;
}
}
/**
* Your ZigzagIterator object will be instantiated and called as such:
* ZigzagIterator i = new ZigzagIterator(v1, v2);
* while (i.hasNext()) v[f()] = i.next();
*/