我需要将绘制的矩形鼠标透明,以便查看桌面.
以下代码绘制了我的矩形.我应该添加什么来获得它？
感谢帮助

public void start(Stage primaryStage) {
    Group group = new Group();

    Rectangle rect = new Rectangle(20,20,200,200);

    rect.setArcHeight(15);
    rect.setArcWidth(15);

    rect.setStroke(Color.BLACK);
    group.getChildren().add(rect);

    Scene scene = new Scene(group, 300, 200);
    primaryStage.setScene(scene);
    primaryStage.show();
}

解决方法:

由于JavaFX中的屏幕图形是分层结构,要显示桌面,您还需要使舞台和场景透明,并使用形状“算术”：

@Override
public void start(Stage stage) {
    Group group = new Group();
    Rectangle rect = new Rectangle(0, 0, 350, 300);
    Rectangle clip = new Rectangle(20, 20, 200, 200);
    clip.setArcHeight(15);
    clip.setArcWidth(15);

    Shape shape = Shape.subtract(rect, clip);

    shape.setFill(Color.GRAY);
    group.getChildren().add(shape);
    Scene scene = new Scene(group);
    scene.setFill(Color.TRANSPARENT);
    stage.initStyle(StageStyle.TRANSPARENT);
    stage.setScene(scene);
    stage.show();
}

稍后您可以向窗格/组添加可拖动功能.