我试图检测对tableview的随机单元格的双击.
检测到doubleclick不是问题,而是哪个单元已被双击.
table.addEventFilter(MouseEvent.MOUSE_CLICKED, new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent event) {
if (event.getClickCount() > 1) {
System.out.println("double clicked!");
TableCell c = (TableCell) event.getSource();
System.out.println("Cell text: " + c.getText());
}
}
});
这是我建立表格的方式:
private void BuildTable() throws Exception
{
/*Some initialisations etc*/
for(int i=0; i<result.getMetaData().getColumnCount();i++)
{
final int j = i;
TableColumn col = new TableColumn(result.getMetaData().getColumnName(i+1));
col.setCellValueFactory(new Callback<CellDataFeatures<ObservableList,String>,ObservableValue<String>>(){
public ObservableValue<String> call(CellDataFeatures<ObservableList, String> param)
{
return new SimpleStringProperty(param.getValue().get(j).toString());
}
});
table.getColumns().addAll(col);
}
while(result.next()){
ObservableList<String> row = FXCollections.observableArrayList();
for(int i = 1; i<=result.getMetaData().getColumnCount();i++){
row.add(result.getString(i));
}
data.add(row);
}
table.setItems(data);
}catch(Exception e){
e.printStackTrace();
}
}
真正的问题是我不能只是将类型转换为TableCell.
有人可以帮我吗?我会很感激.
解决方法:
您无需在表中注册处理程序,而需要在表单元格中注册处理程序.为此,请在适当的TableColumn上使用单元格工厂.
例如,将以下代码添加到standard table example(清单13.6).
firstNameCol.setCellFactory(new Callback<TableColumn<Person, String>, TableCell<Person, String>>() {
@Override
public TableCell<Person, String> call(TableColumn<Person, String> col) {
final TableCell<Person, String> cell = new TableCell<Person, String>() {
@Override
public void updateItem(String firstName, boolean empty) {
super.updateItem(firstName, empty);
if (empty) {
setText(null);
} else {
setText(firstName);
}
}
};
cell.addEventHandler(MouseEvent.MOUSE_CLICKED, new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent event) {
if (event.getClickCount() > 1) {
System.out.println("double click on "+cell.getItem());
}
}
});
return cell ;
}
});