Syntax
extract_datetime::=
Purpose
EXTRACT
extracts and returns the value of a specified datetime field from a datetime or interval expression. The expr
can be any expression that evaluates to a datetime or interval data type compatible with the requested field:
-
If
YEAR
orMONTH
is requested, thenexpr
must evaluate to an expression of data typeDATE
,TIMESTAMP
,TIMESTAMP
WITH
TIME
ZONE
,TIMESTAMP
WITH
LOCAL
TIME
ZONE
, orINTERVAL
YEAR
TO
MONTH
. -
If
DAY
is requested, thenexpr
must evaluate to an expression of data typeDATE
,TIMESTAMP
,TIMESTAMP
WITH
TIME
ZONE
,TIMESTAMP
WITH
LOCAL
TIME
ZONE
, orINTERVAL
DAY
TO
SECOND
. -
If
HOUR
,MINUTE
, orSECOND
is requested, thenexpr
must evaluate to an expression of data typeTIMESTAMP
,TIMESTAMP
WITH
TIME
ZONE
,TIMESTAMP
WITH
LOCAL
TIME
ZONE
, orINTERVAL
DAY
TO
SECOND
.DATE
is not valid here, because Oracle Database treats it as ANSIDATE
data type, which has no time fields. -
If
TIMEZONE_HOUR
,TIMEZONE_MINUTE
,TIMEZONE_ABBR
,TIMEZONE_REGION
, orTIMEZONE_OFFSET
is requested, thenexpr
must evaluate to an expression of data typeTIMESTAMP
WITH
TIME
ZONE
orTIMESTAMP
WITH
LOCAL
TIME
ZONE
.
EXTRACT
interprets expr
as an ANSI datetime data type. For example, EXTRACT
treats DATE
not as legacy Oracle DATE
but as ANSI DATE
, without time elements. Therefore, you can extract only YEAR
, MONTH
, and DAY
from a DATE
value. Likewise, you can extract TIMEZONE_HOUR
and TIMEZONE_MINUTE
only from the TIMESTAMP
WITH
TIME
ZONE
data type.
When you specify TIMEZONE_REGION
or TIMEZONE_ABBR
(abbreviation), the value returned is a VARCHAR2
string containing the appropriate time zone region name or abbreviation. When you specify any of the other datetime fields, the value returned is an integer value of NUMBER
data type representing the datetime value in the Gregorian calendar. When extracting from a datetime with a time zone value, the value returned is in UTC. For a listing of time zone region names and their corresponding abbreviations, query the V$TIMEZONE_NAMES
dynamic performance view.
1. 获取当前日期中的年份
SQL> select extract(year from sysdate) as "year" from dual
2 /
year
----------
2012
2. 获取当前日期中的月份
SQL> select extract(month from sysdate) as "month" from dual
2 /
month
----------
8
3. 获取当前日期中的日
SQL> select extract(day from date'2012-12-28') as "day" from dual
2 /
day
----------
28
转载于:https://www.cnblogs.com/oradragon/archive/2012/08/30/2664674.html