运行雄辩的联接查询时,我得到了一些意外的结果.通过使用完全相同的查询,我得到两个不同的结果.一个使用DB :: raw()运行,第二个使用Eloquent.

在口才查询中,与

其中squad_user.leave_time> = seasons.start_time

丢失,不会包含在结果集中.符合条件的用户

或squad_user.leave为null

将包括在内.

这是两个查询结果的唯一区别.原始查询实际上产生所需的结果集.

真正令我困惑的是,如果我同时查询Laravel和MySQL的查询日志,则在同时运行原始查询和Eloquent查询时会得到完全相同的查询.

原始查询(运行口才查询时,我从查询日志中获得的实际查询)

return \DB::select(\DB::raw('
        select users.*
        from users
        inner join squad_user on users.id = squad_user.user_id
        inner join seasons on squad_user.squad_id = seasons.squad_id
        where squad_user.join_time <= seasons.end_time
        and (squad_user.leave_time >= seasons.start_time or squad_user.leave_time is null)
        and seasons.id = :seasonId
    '),
    ['seasonId' => 3]
);

口才查询

return User::join('squad_user', 'users.id', '=', 'squad_user.user_id')
           ->join('seasons', 'squad_user.squad_id', '=', 'seasons.squad_id')
           ->where('squad_user.join_time', '<=', 'seasons.end_time')
           ->where(function ($query)
           {
               $query->where('squad_user.leave_time', '>=', 'seasons.start_time')
                     ->orWhereNull('squad_user.leave_time');
           })
           ->where('seasons.id', 3)
           ->get(['users.*']);

Laravel的雄辩查询日志

select `users`.*
from `users`
inner join `squad_user` on `users`.`id` = `squad_user`.`user_id`
inner join `seasons` on `squad_user`.`squad_id` = `seasons`.`squad_id`
where `squad_user`.`join_time` <= seasons.end_time
and (`squad_user`.`leave_time` >= seasons.start_time or `squad_user`.`leave_time` is null)
and `seasons`.`id` = 3
{"bindings":["seasons.end_time","seasons.start_time",3],"time":0.38,"name":"mysql"}

MySQL对口才查询的general_log

select `users`.*
from `users`
inner join `squad_user` on `users`.`id` = `squad_user`.`user_id`
inner join `seasons` on `squad_user`.`squad_id` = `seasons`.`squad_id`
where `squad_user`.`join_time` <= ?
and (`squad_user`.`leave_time` >= ? or `squad_user`.`leave_time` is null)
and `seasons`.`id` = ? 

MySQL在raw查询上的general_log

select users.*
            from users
            inner join squad_user on users.id = squad_user.user_id
            inner join seasons on squad_user.squad_id = seasons.squad_id
            where squad_user.join_time <= seasons.end_time
            and (squad_user.leave_time >= seasons.start_time or squad_user.leave_time is null)
            and seasons.id = ?

我会很感激这里的任何指示,因为我很失落.

解决方法:

where绑定第三参数并将其通常视为字符串,除非您通过使用raw语句告诉它不这样做. DB :: raw或whereRaw将为您工作：

return User::join('squad_user', 'users.id', '=', 'squad_user.user_id')
       ->join('seasons', 'squad_user.squad_id', '=', 'seasons.squad_id')
       ->where('squad_user.join_time', '<=', DB::raw('seasons.end_time'))
       ->where(function ($query)
       {
           $query->where('squad_user.leave_time', '>=', DB::raw('seasons.start_time'))
                 ->orWhereNull('squad_user.leave_time');
       })
       ->where('seasons.id', 3)
       ->get(['users.*']);