public static void main(String[] args) {

         LinkedList q = new LinkedList();

         q.add(8);

         q.add(9);

         q.add(10);

         //出库12

         int outNumber=12;//模拟fifo

         for(int i=0;i<q.size();i++){

             int number=(Integer) q.get(i);

             int resetNumber=number-outNumber;

             System.out.println("循环次数:"+(i+1));

             if(resetNumber<0){//库存数量不充足

                 outNumber-=number;

                 System.out.println(0);

             }else{

                 System.out.println("d"+(number-outNumber));//剩余的数量

                 break;

             }

         }

     }