//header.h #ifndef _HEADER_H #define _HEADER_H #define defaultSize 128 #include<iostream> #include<assert.h> #include<string.h> using namespace std; class myString { private: char *ch; int curLength; int maxSize; public: myString(int sz=defaultSize);//三种构造方式 myString(const char *init); myString(const myString& ob); ~myString(){delete []ch;} void print();//打印字符串 int Length()const; myString operator()(int pos, int len);//字符串切片操作 bool operator == (myString& ob)const;//符号重载 bool operator != (myString& ob)const; bool operator !()const;//判断字符串是否为空 myString& operator = (const myString& ob);//临时变量不能作为非const的引用参数 myString& operator +=(myString& ob); char& operator[](int i);//返回字符串第i个位置的字符 int Find(myString &pat)const;//查子串,返回第一个子串起始位置,不存在返回-1 }; int myString::Find(myString &pat)const { if(pat.curLength > this->curLength) return -1; int i=0, j=0; while(this->ch[i]!=pat.ch[0] && i<this->curLength)//在母串匹配子串第一个字符 { ++i; } CIRCLE: while(this->ch[i]!=pat.ch[0] && i<this->curLength)//在母串匹配子串第一个字符 { ++i; } if(i==this->curLength)//抵达母串最大长度还没找到。返回-1 return -1; else if(this->ch[i] == pat.ch[0])//找到了继续匹配 { ++i, j=1; while(i<this->curLength && j<pat.curLength && this->ch[i]==pat.ch[j]) { ++i; ++j; } if(j == pat.curLength)//抵达子串最大长度,则说明子串在母串内,返回位置 return i-j+1; else if(i < this->curLength)//没找到子串且母串未抵达最大位置,继续在母串匹配子串第一个字符 goto CIRCLE; else //母串抵达最大位置且没找到子串,返回-1 return -1; } } char& myString::operator[](int i) { assert(i<=this->curLength&&i>0); return this->ch[i-1]; } myString& myString::operator+=(myString& ob)//这个函数直接strcat(this->ch, ob.ch)就可以成功拼接,但是若这样操作则无法知道字符串的最大长度 { myString tmp(*this); delete [] this->ch; this->ch = new char[this->maxSize+ob.maxSize]; strcpy(this->ch, tmp.ch); strcat(this->ch, ob.ch); this->curLength += ob.curLength; this->maxSize += ob.maxSize; delete[] tmp.ch; return *this; } bool myString::operator !()const { return this->curLength==0; } bool myString::operator != (myString& ob)const { return strcmp(this->ch, ob.ch) == 0 ? false : true; } bool myString::operator == (myString& ob)const { return strcmp(this->ch, ob.ch) == 0 ? true : false; } myString& myString::operator = (const myString& ob) { if(&ob!=this) { delete[]ch; this->ch = new char[ob.maxSize]; this->maxSize = ob.curLength; strcpy(this->ch, ob.ch); this->curLength = ob.curLength; } else { cerr<<"String copy error\n"; } return *this; } myString myString::operator()(int pos, int len) { myString temp; if(pos<0 || len<=0 || pos+len-1>=this->maxSize) { temp.curLength = 0; temp.ch[0] = '\0'; } else { if(pos+len-1 >= this->curLength) len = this->curLength-pos; temp.curLength = len; for(int i=0,j=pos; i<len; ++i,++j) temp.ch[i] = this->ch[j]; temp.ch[len] = '\0'; } return temp; } int myString::Length()const { return this->curLength; } void myString::print() { cout<<this->ch<<endl; } myString::myString(int sz) { this->maxSize = sz; this->ch = new char[this->maxSize+1]; if(this->ch == NULL) { cerr<<"Allocation ERROR\n"; exit(1); } this->curLength = 0; ch[0] = '\0'; } myString::myString(const char *init) { int len = strlen(init); this->maxSize = (len > defaultSize) ? len : defaultSize; this->ch = new char[this->maxSize+1]; if(this->ch == NULL) { cerr<<"Application Memory ERROR\n"; exit(1); } this->curLength = len; strcpy(this->ch, init); } myString::myString(const myString& ob) { this->maxSize = ob.maxSize; this->ch = new char[this->maxSize+1]; if(this->ch == NULL) { cerr<<"Application Memory ERROR\n"; exit(1); } this->curLength = ob.curLength; strcpy(this->ch, ob.ch); } #endif
#include"header.h" int main() { myString st(10), st1("ABCDEFG"); myString st2(st1); //st.print(), st1.print(), st2.print(); st = st1(0, 4); cout<<"st = "; st.print(); cout<<"st1 = "; st1.print(); st += st1; cout<<"st + st1 = "; st.print(); char a = st[5]; cout<<a<<endl; myString st3("EFGH"); cout<<st1.Find(st3)<<endl; st3 = st3(0, 3); cout<<st1.Find(st3)<<endl; return 0; }
在实现自定义字符串类的时候遇到两个问题,一个是=号重载时,参数必须为const才能正常赋值。
https://www.cnblogs.com/area-h-p/p/11498481.html
另一个就是模式匹配寻找子串。
我实现的寻找子串的方法只需将母串遍历一遍,即可得到子串位置。
具体操作就是先在母串找到子串的第一个字符,然后检查后面字符是否也同样相同,不同继续在母串后边找与子串第一个字符相同的字符,相同则继续循环匹配,直到抵达子串或母串最大长度,若抵达子串最大长度,即找到子串位置,若没有到母串最大长度,则继续在母串后边找与子串第一个字符相同的字符。以此循环。