我有以下MySQL：

select  `car`.`ID` AS `ID`,
    `title`,`text`
    from `car` 
    LEFT JOIN `truck` as bigcar ON bigcar.`ID` = `car`.`truckID` 
    WHERE `ID` ='1';

出于某种原因,我得到了

Column ‘ID’ in where clause is ambiguous

出于复杂的代码原因,我不会将别名重命名为其他内容(例如ID2)
这不应该工作吗？

解决方法:

您需要在where子句中指定用于id的表.否则,查询将不知道要使用哪一个,因为在两个表中具有相同的列名

SELECT
 `car`.`ID` AS `ID`, `title`,`text`
FROM `car` 
LEFT JOIN `truck` as bigcar ON bigcar.`ID` = `car`.`truckID` 
WHERE `car`.`ID` ='1';

或者如果你想要bigcar ID,你将不得不使用：

WHERE `bigcar`.`ID` ='1'; // not truck but bigcar which is the alias you created