Codeforces 1092E Minimal Diameter Forest

Minimal Diameter Forest

首先我们找出每个连通块中的特殊点, 特殊点的定义是到各种个连通块中距离的最大值最小的点,

每个连通块肯定通过特殊点连到其他连通块, 我们把有最大值的特殊点当作根, 然后其他点直接接在这个点中, 形成菊花图。

#include<bits/stdc++.h>
#define LL long long
#define fi first
#define se second
#define mk make_pair
#define PLL pair<LL, LL>
#define PLI pair<LL, int>
#define PII pair<int, int>
#define SZ(x) ((int)x.size())
#define ull unsigned long long using namespace std; const int N = + ;
const int inf = 0x3f3f3f3f;
const LL INF = 0x3f3f3f3f3f3f3f3f;
const int mod = 1e9 + ;
const double eps = 1e-;
const double PI = acos(-); int n, m, cnt, mx, DIA, belong[N], mn[N], who[N], id[N], dia[N];
vector<int> G[N]; void dfs(int u) {
belong[u] = cnt;
for(auto& v : G[u])
if(!belong[v]) dfs(v);
}
void dfs2(int u, int fa, int depth) {
mx = max(mx, depth);
for(auto& v : G[u])
if(v != fa) dfs2(v, u, depth + );
} bool cmp(const int& x, const int& y) {
return mn[x] > mn[y];
} int main() {
memset(mn, inf, sizeof(mn));
scanf("%d%d", &n, &m);
for(int i = ; i <= m; i++) {
int u, v; scanf("%d%d", &u, &v);
G[u].push_back(v);
G[v].push_back(u);
}
for(int i = ; i <= n; i++) {
if(!belong[i]) ++cnt, dfs(i);
}
for(int i = ; i <= n; i++) {
mx = ;
dfs2(i, , );
if(mx < mn[belong[i]]) {
mn[belong[i]] = mx;
who[belong[i]] = i;
}
dia[belong[i]] = max(dia[belong[i]], mx);
}
for(int i = ; i <= cnt; i++) {
id[i] = i;
DIA = max(DIA, dia[i]);
}
sort(id + , id + + cnt, cmp);
if(cnt >= ) DIA = max(DIA, mn[id[]] + mn[id[]] + );
if(cnt >= ) DIA = max(DIA, mn[id[]] + mn[id[]] + );
printf("%d\n", DIA);
for(int i = ; i <= cnt; i++) printf("%d %d\n", who[id[]], who[id[i]]);
return ;
} /*
*/
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