我使用spring-boot来开发后端服务.有一种方案可以比较2-beans(一个是DB对象,另一个是客户端请求的对象)并返回“new element”,“modified element”,如果没有更改,则返回false. 2豆的格式如下
"sampleList":{
"timeStamp":"Thu, 21 Jun 2018 07:57:00 +0000",
"id":"5b19441ac9e77c000189b991",
"sampleListTypeId":"type001",
"friendlyName":"sample",
"contacts":[
{
"id":"5b05329cc9e77c000189b950",
"priorityOrder":1,
"name":"sample1",
"relation":"Friend",
"sampleInfo":{
"countryCode":"91",
"numberType":"MOBILE",
"numberRegion":"IN"
}
},
{
"id":"5b05329cc9e77c000189b950",
"priorityOrder":1,
"name":"sample2",
"relation":"Friend",
"sampleInfo":{
"countryCode":"91",
"numberType":"MOBILE",
"numberRegion":"IN"
}
}
]
}
我在java中浏览了关于这种情况的bean比较的网络,但我找不到任何更简单的解决方案,但找到了一些很酷的JSON解决方案.我可以看到GSON的一些解决方案,但它不会返回客户端对象包含“新元素”和“更改元素”.有没有办法在JSON或JAVA中返回更新和修改过的元素?你的帮助应该是值得的.即使是暗示对我来说也是一个很好的开始.
解决方法:
将JSON文档读取为Maps并进行比较
您可以将两个JSON文档都读为Map<K, V>
.请参阅以下Jackson和Gson的示例:
ObjectMapper mapper = new ObjectMapper();
TypeReference<HashMap<String, Object>> type =
new TypeReference<HashMap<String, Object>>() {};
Map<String, Object> leftMap = mapper.readValue(leftJson, type);
Map<String, Object> rightMap = mapper.readValue(rightJson, type);
Gson gson = new Gson();
Type type = new TypeToken<Map<String, Object>>(){}.getType();
Map<String, Object> leftMap = gson.fromJson(leftJson, type);
Map<String, Object> rightMap = gson.fromJson(rightJson, type);
然后使用Guava的Maps.difference(Map<K, V>, Map<K, V>)
来比较它们.它返回一个MapDifference<K, V>
实例:
MapDifference<String, Object> difference = Maps.difference(left, right);
如果您对结果不满意,可以考虑展平地图然后进行比较.它将提供更好的比较结果,尤其是对于嵌套对象和数组.
创建平面地图以进行比较
要平整地图,您可以使用:
public final class FlatMapUtil {
private FlatMapUtil() {
throw new AssertionError("No instances for you!");
}
public static Map<String, Object> flatten(Map<String, Object> map) {
return map.entrySet().stream()
.flatMap(FlatMapUtil::flatten)
.collect(LinkedHashMap::new, (m, e) -> m.put("/" + e.getKey(), e.getValue()), LinkedHashMap::putAll);
}
private static Stream<Map.Entry<String, Object>> flatten(Map.Entry<String, Object> entry) {
if (entry == null) {
return Stream.empty();
}
if (entry.getValue() instanceof Map<?, ?>) {
return ((Map<?, ?>) entry.getValue()).entrySet().stream()
.flatMap(e -> flatten(new AbstractMap.SimpleEntry<>(entry.getKey() + "/" + e.getKey(), e.getValue())));
}
if (entry.getValue() instanceof List<?>) {
List<?> list = (List<?>) entry.getValue();
return IntStream.range(0, list.size())
.mapToObj(i -> new AbstractMap.SimpleEntry<String, Object>(entry.getKey() + "/" + i, list.get(i)))
.flatMap(FlatMapUtil::flatten);
}
return Stream.of(entry);
}
}
它使用RFC 6901中定义的JSON指针表示法作为键,因此您可以轻松找到值.
例
请考虑以下JSON文档:
{
"name": {
"first": "John",
"last": "Doe"
},
"address": null,
"birthday": "1980-01-01",
"company": "Acme",
"occupation": "Software engineer",
"phones": [
{
"number": "000000000",
"type": "home"
},
{
"number": "999999999",
"type": "mobile"
}
]
}
{
"name": {
"first": "Jane",
"last": "Doe",
"nickname": "Jenny"
},
"birthday": "1990-01-01",
"occupation": null,
"phones": [
{
"number": "111111111",
"type": "mobile"
}
],
"favorite": true,
"groups": [
"close-friends",
"gym"
]
}
以下代码比较它们并显示差异:
Map<String, Object> leftFlatMap = FlatMapUtil.flatten(leftMap);
Map<String, Object> rightFlatMap = FlatMapUtil.flatten(rightMap);
MapDifference<String, Object> difference = Maps.difference(leftFlatMap, rightFlatMap);
System.out.println("Entries only on the left\n--------------------------");
difference.entriesOnlyOnLeft()
.forEach((key, value) -> System.out.println(key + ": " + value));
System.out.println("\n\nEntries only on the right\n--------------------------");
difference.entriesOnlyOnRight()
.forEach((key, value) -> System.out.println(key + ": " + value));
System.out.println("\n\nEntries differing\n--------------------------");
difference.entriesDiffering()
.forEach((key, value) -> System.out.println(key + ": " + value));
它将产生以下输出:
Entries only on the left
--------------------------
/address: null
/phones/1/number: 999999999
/phones/1/type: mobile
/company: Acme
Entries only on the right
--------------------------
/name/nickname: Jenny
/groups/0: close-friends
/groups/1: gym
/favorite: true
Entries differing
--------------------------
/birthday: (1980-01-01, 1990-01-01)
/occupation: (Software engineer, null)
/name/first: (John, Jane)
/phones/0/number: (000000000, 111111111)
/phones/0/type: (home, mobile)