我正在尝试使用gson将这个返回的JSON转换成某种形式
数据结构使我可以提取有用的数据.

例如：

http://search.twitter.com/search.json?q=test&rpp=1

返回：

{
    "completed_in":0.028,
    "max_id":196386333906837504,
    "max_id_str":"196386333906837504",
    "next_page":"?page=2&max_id=196386333906837504&q=test&rpp=1",
    "page":1,
    "query":"test",
    "refresh_url":"?since_id=196386333906837504&q=test",
       "results":[
          {
             "created_at":"Sat, 28 Apr 2012 23:52:05 +0000",
             "from_user":"della_ky",
             "from_user_id":525641596,
             "from_user_id_str":"525641596",
             "from_user_name":"kydella modeste",
             "geo":null,
             "id":196386333906837504,
             "id_str":"196386333906837504",
             "iso_language_code":"en",
             "metadata":{
                "result_type":"recent"
             },
             "profile_image_url":"http:\/\/a0.twimg.com\/profile_images\/2159990525\/webcam-toy-photo3_20_2__normal.jpg",
             "profile_image_url_https":"https:\/\/si0.twimg.com\/profile_images\/2159990525\/webcam-toy-photo3_20_2__normal.jpg",
             "source":"<a href="http:\/\/mobile.twitter.com" rel="nofollow">Mobile Web<\/a>",
             "text":"RT @Y__U__NOOO: #SongsIKnowOffByHeart ALL SONGS I LISTEN TO. BRAIN, Y U NO REMEMBER TEST ANSWERS LIKE THAT?!?",
             "to_user":null,
             "to_user_id":null,
             "to_user_id_str":null,
             "to_user_name":null
          }
       ],
       "results_per_page":1,
       "since_id":0,
       "since_id_str":"0"
    }

最终,我希望能够输出一个推文列表
发件人的姓名和推文的日期/时间.

我已经阅读了gson文档,但它已经过了我的脑海
说实话 – 我有很多新概念.

我是否需要定义一个完全映射到结构的类
JSON以便然后填充该类的实例？如果是这样的话
似乎非常不灵活/费力.理想情况下,我正在寻找一些东西
它将处理任何形式的JSON,并给我一个我可以使用的结构
自动…

有人能给我一些指示吗？对此更新 – 更多
详细的,用最少的音节的话来说就更好了！

更新 – 感谢我已经对此做出的回应,我已经开始将一个类放在一起来捕获twitter JSON.但是,由于JSON有一个嵌入的对象ArrayList,我有点挣扎……到目前为止,我有

public class tweetData {
    private double completed_in;
    private long max_id;
    private long max_id_str;
    private String next_page;
    private int page;
    private String query;
    private String refresh_url;
    private List<tweetDetails> tweets = new ArrayList<tweetDetails>();
}

和

public class tweetDetails {
    private String created_at;
    private String from_user;
    private long from_user_id;
    private long from_user_id_str;
    private String from_user_name;
    private String geo;
    private long id;
    private long id_str;
    private String iso_language_code;
//  "metadata":
//  {
//  "result_type":"recent"
//  },
    private String profile_image_url;
    private String profile_image_url_https;
    private String source;
    private String text;
    private String to_user;
    private String to_user_id;
    private String to_user_id_str;
    private String to_user_name;
}

我正在实例化

URI uri = new URI("http", "search.twitter.com", "/search.json", "q="+ searchTerms + "&rrp=" + RRP, null);
URL twitterSearch = uri.toURL();
URLConnection yc = twitterSearch.openConnection();
JsonReader reader = new JsonReader(new InputStreamReader(yc.getInputStream()));
Gson gson = new Gson();
tweetData data = gson.fromJson(reader, tweetData.class);
System.out.println(data);

基本名称：正确填充值但ArrayList不正确填充.

tweetData : 0.17196614959919140865196614959919140865?page=2&max_id=196614959919140865&q=test1test?since_id=196614959919140865&q=testSIZE 0[]

所以,我还在苦苦挣扎 – 任何更多的提示非常感谢！

蒂亚,
汤姆

解决方法:

Do I need to define a class which maps exactly to the structure of the JSON in order to then populate an instance of that class? If so this seems very inflexible/laborious.

是. GSON是一个可用于将Java对象转换为其JSON表示的库.它还可用于将JSON字符串转换为等效的Java对象.这非常强大,因为您可以从JSON表示自动实例化Java对象.假设您的JSON没有更改其结构,您只需要定义一次适当的Java对象表示.

Ideally I’m looking for something which will handle JSON in any form and give me a structure I can use automatically…

但是,如果您不想进行自动序列化/反序列化,那么请尝试查看更简单的库,例如java.net/projects/jsonp.

您只需查询键即可从中提取内容：

final JSONObject json = new JSONObject(theJsonString);
final String id = json.getString("max_id");
final JSONArray results = json.getJSONArray("results");
final String user = results.getJSONObject(2).getString("from_user");