Codeforces Round #257 (Div. 2 ) B. Jzzhu and Sequences

B. Jzzhu and Sequences
time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Jzzhu has invented a kind of sequences, they meet the following property:

Codeforces Round #257 (Div. 2 ) B. Jzzhu and Sequences

You are given x and y, please calculate fn modulo 1000000007 (109 + 7).

Input

The first line contains two integers x and y (|x|, |y| ≤ 109). The second line contains a single integer n (1 ≤ n ≤ 2·109).

Output

Output a single integer representing fn modulo 1000000007 (109 + 7).

Sample test(s)
Input
2 3
3
Output
1
Input
0 -1
2
Output
1000000006
Note

In the first sample, f2 = f1 + f3, 3 = 2 + f3, f3 = 1.

In the second sample, f2 =  - 1;  - 1 modulo (109 + 7) equals (109 + 6).

 #include<iostream>
#include<string.h>
#include<stdio.h>
#include<ctype.h>
#include<algorithm>
#include<stack>
#include<queue>
#include<set>
#include<math.h>
#include<vector>
#include<map>
#include<deque>
#include<list>
using namespace std;
#define M 1000000007
int main()
{
__int64 n,a[];
scanf("%I64d%I64d%I64d", &a[], &a[], &n);
a[]=a[]%M;
a[]=a[]%M;
a[]=(a[]-a[])%M;
a[]=(-a[])%M;
a[]=(-a[])%M;
a[]=(a[]-a[])%M;
printf("%I64d\n", a[(n-)%]>=? a[(n-)%] : a[(n-)%]+M); return ;
}
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