我在这里有一个计数代码:
HTML:
<div id="value">700</div>
<div id="value2">1000</div>
JavaScript的:
function animateValue(id, start, end, duration) {
var start= 0 ;
var end = parseInt(document.getElementById(id).textContent, 10);
var duration = 10000;
var range = end - start;
var current = start;
var increment = end > start? 1 : -1;
var stepTime = Math.abs(Math.floor(duration / range));
var obj = document.getElementById(id);
var timer = setInterval(function() {
current += increment;
obj.innerHTML = current;
if (current == end) {
clearInterval(timer);
}
}, stepTime);
}
animateValue("value2",0,0,0);
animateValue("value",0,0,0);
在此代码中,从0开始到结束,持续时间为10000毫秒.当接近结束时,如何将此持续时间设置为慢于此?
例如:
数字:0到100.
持续时间:50ms至10ms.
解决方法:
使用一些缓动函数而不是以恒定速率递增.
但是,请注意,由于每个值的增量需要一些执行时间(使用此setTimeout方法无法解决),因此总执行时间可能始终至少有些不准确.价值越高,问题就越严重.
//No easing
function constant (duration, range, current) {
return duration / range;
}
//Linear easing
function linear (duration, range, current) {
return ((duration * 2) / Math.pow(range, 2)) * current;
}
//Quadratic easing
function quadratic (duration, range, current) {
return ((duration * 3) / Math.pow(range, 3)) * Math.pow(current, 2);
}
function animateValue(id, start, duration, easing) {
var end = parseInt(document.getElementById(id).textContent, 10);
var range = end - start;
var current = start;
var increment = end > start? 1 : -1;
var obj = document.getElementById(id);
var startTime = new Date();
var offset = 1;
var remainderTime = 0;
var step = function() {
current += increment;
obj.innerHTML = current;
if (current != end) {
setTimeout(step, easing(duration, range, current));
}
else {
console.log('Easing: ', easing);
console.log('Elapsed time: ', new Date() - startTime)
console.log('');
}
};
setTimeout(step, easing(duration, range, start));
}
animateValue("value", 0, 10000, constant);
animateValue("value2", 0, 10000, linear);
animateValue("value3", 0, 10000, quadratic);
<div id="value">100</div>
<div id="value2">100</div>
<div id="value3">100</div>